STAT 479 Test 2 Spring 2014 April 1, 2014

Size: px
Start display at page:

Download "STAT 479 Test 2 Spring 2014 April 1, 2014"

Transcription

1 TAT 479 Test pring 014 April 1, (5 points) You are given the following grouped data: Calculate F (4000) 5 using the ogive. Amount of claims Number of Claims 0 to to to 10, ,000 and above F 5 18 (500) F 5 3 (10, 000) F 5 (4000) is determined using linear interpolation under the ogive F 5 10, (4000) , ,

2 . For a warranty insurance policy, you are given the following frequency distribution: Number of Claims Probability You are also given the following severity distribution: Amount of Claim Probability Weibo Warranty Company buys stop loss insurance from pears top Loss Company which will pay for aggregate claims in excess of pears charges 15% of the Net top Loss Premium for this coverage. a. (10 points) Determine f (x). f (0) Pr( N 0) 0.05 f (1000) Pr( N 1) Pr( X 1000) (0.)(0.4) 0.08 f (000) Pr( N ) Pr( Both X 1000) Pr( N 1) Pr( X 000) (0.3)(0.4) (0.)(0.5) f (3000) Pr( N ) Pr( One X 1000 and Other X 000) Pr( N 1) Pr( X 3000) (0.3)()(0.4)(0.5) (0.)(0.35) 0.13 f (4000) Pr( N ) Pr( One X 1000 and Other X 3000) Pr( N ) Pr(Both X 000) (0.3)()(0.4)(0.35) (0.3)(0.5) f (5000) Pr( N ) Pr( One X 000 and Other X 000) (0.3)()(0.5)(0.35) f N Both X (6000) Pr( ) Pr( 3000) (0.3)(0.35)

3 b. (6 points) Calculate the amount that Weibo will pay to pears. E[( 4000) ] E[ ] E[ 4000] E[ ] E[ N] E[ X ] (0.5)(0) (0.)(1) (0.3)() (0.4)(1000) (0.5)(000) (0.35)(3000) (0.8)(1950) 1560 E [ 4000] (0.5)(0) (0.08)(1000) (0.098)(000) (0.13)(3000) ( )(4000) 1434 E[( 4000) ] E[ ] E[ 4000] Premium (1.5)(16) Alternatively, we can calculate it directly as: E[( 4000) ] ( )(0.055) ( )( ) 16 Premium (1.5)(16)

4 3. Gloria from Gong Consulting has been hired by the Purdue athletic department to determine the transfer rate of athletes in the Purdue basketball program. he gathers the following data for a five year period with all times in years: Player tart Date in tudy Termination Date Termination Reason Graduation 0 1 Flunked Out Graduation Transfer Transfer Graduation Transfer Transfer 9 5 End of tudy 10 5 End of tudy Illness 1 4 Transfer End of tudy End of tudy End of tudy Gloria decides to use the Kaplan Meier product limit estimator to estimate (3.7) 15. a. (7 points) Determine (3.7) 15 as calculated by Gloria. y s 3 4 r (3.7) b. (5 points) Calculate the variance of this estimate using the Greenwood Approximation. 1 Var[ 15(3.7)] (0.75) (11)(11 ) (1)(1 1)

5 4. Wenchu has selected the following sample of claims: Wenchu creates a continuous distribution from this sample using a kernel density estimator with a uniform kernel with a bandwidth of. a. (8 points) Calculate f (4.5) and F (4.5) produced by the kernel density model. y 1 4 1/10 x 6 5 1/10 3x /10 4x /10 5x /10 6 x /10 7 x /10 1 x 16 p x k (4.5) 1/ b 1/ 4 =0.5 for y 4.5 y and zero elsewhere y f (4.5) p k (4.5) p k (4.5) p k (4.5) 0(for y >6.5)= (0.1)(0.5)+(0.1)(0.5)+(0.3)(0.5)=0.15 K y 4.5 y (4.5) for y 4.5 y ; 1 for y<.5 and 0 for y>6.5 4 F p4 K4 p5 K5 p6 K6 y (4.5) (4.5) (4.5) (4.5) 0(for >6.5)= (0.1) +(0.1) +(0.3) =

6 b. (3 points) Calculate the mean and variance of the kernel density model. Mean of kernel density model = Mean of Empiral Distribution = 4 5 (3)(6) ()(7) b Variance of kernel density model = Variance of Empiral Distribution (3)(6) ()(7) (7.)

7 5. (10 points) Claims for comprehensive coverage offered by Chellberg Car Assurance Company are distributed as a Pareto distribution with 5 and 000. Chellberg s chief actuary, Devin, wants to create a discrete distribution for claims using a span of 500. Devin asks Emily to discretize the claims using the method of rounding. Let probability that Emily assigns to the range of (750, 150). ROUNDING f be the Devin asks Brandon to discretize the claims using the method of local moment matching where the discretized distribution will have the same mean as the Pareto distribution. Let MomentMatching f be the probability that Brandon assigns to the range of (750, 150). ROUNDING MomentMatching Calculate 1000( f f ). 5 5 ROUNDING f F(150) F(750) f MomentMatching E[ X 1000] E[X ( )] E[X ( )] Answer (1000)( )

8 6. (10 points) The Dai Dog Insurance Company provides life insurance on new born puppies. Dai wants to understand the expected claims that she will be paying during the next year. Dora who is the President of the Dai believes that large dogs and small dogs have different mortality and different amount of claims. he has sorted the Dai s policies into two portfolios. The following is the information on the portfolios: Portfolio Number Probability of Death of Policies during Next Year Distribution of Death Benefit mall Dogs 10, Uniform from 1000 to 500 Large Dogs 8, policies have a benefit of policies have a benefit of 3000 Dora decides that she wants to hold a reserve equal to E[ ] 1.5 Var() where is the random variable representing the aggregate claims to be paid during the next year. Calculate the reserve that Dora will hold. This question could be worked two ways. One way (the proper way) is to split the Large Dog portfolio into two portfolios since we know the actual split by count. If you treat the face as a distribution for large dogs as 3/8 are for 3000 and 5/8 are 3000, you get a slightly different answer of 3,653, Credit was given for either answer, but the one below is correct E [ ] (10,000)(0.08) (3000)(0.11)(1500) (5000)(0.11)(3000) 3,545, Var() (10, 000) (0.08) (0.08) (1 0.08) 1 (3000)(0.11)(1 0.11)(1500 ) (5000)(0.11)(1 0.11)(3000 ) 7, 470,35.00 Reserve 3,545, , 470, , 653,

9 7. The Dai Dog Insurance Company provides life insurance on new born puppies. The insurance is paid with a single premium so the only terminations that can occur are from death. Dai hires Kevin to study mortality of 100 dogs insured by Dai. The 100 dogs die as follows: Year of Death Number of Dogs a. (5 points) Calculate H (3) using the Nelson-Åalen estimator. y s r H (3) b. (5 points) Calculate the 80% linear confidence interval for H (3) Var( H (3)) Confidence Interval = (0.4339, ) c. (1 point) Estimate (3) using the Nelson-Åalen estimator. e e H (3) (3)

10 7. (CONTINUED) The Dai Dog Insurance Company provides life insurance on new born puppies. The insurance is paid with a single premium so the only terminations that can occur are from death. Dai hires Kevin to study mortality of 100 dogs insured by Dai. The 100 dogs die as follows: Year of Death Number of Dogs d. ( points) Calculate the unbiased estimator of (3). Number Alive after Time (3) e. ( points) Calculate the variance of the unbiased estimator of (3). Var [ (3)][1 (3)] (0.55)(1 0.55) ( 100(3)) f. ( points) Calculate the unbiased estimator of 3 q n n q n g. ( points) Calculate the variance of the unbiased estimator of 3 q Var [ q ][1 q ] (0.583)( ) 3 3 ( 3q) n 600

11 8. hihao draws the following sample from a uniform distribution on the range of (0, ): a. (1 point) Calculate the unbiased estimate of the mean. X b. ( points) Calculate the unbiased estimate of the variance of this distribution. i nx x (3)(583.33) x 13, n 1 31 c. (4 points) Calculate the mean square error of the estimate in Part a. if ME Var( X ) bias( X ) Var( X ) ( ) 1 Var X n 3 36 bias( X ) 0 since X is an unbiased estimator ME= 0 7,

12 9. (10 points) For a disability policy sold to lumberacks, the number of claims in a year is distributed as geometric distribution with a mean on 0.5. The amount of each claim under these policies is distributed as a gamma distribution with 4 and Li Insurance Company has 8000 policies in force on January 1, 014. Assuming the normal distribution, calculate the 90% confidence interval for the aggregate amount of claims in 014. E[ ] (8000) E[ N] E[X] (8000)[0.05][(4)(5000)] 80,000,000 Var( ) 8000 Var( N) E[ X ] E[ N] Var( X ) 8000 (0.5)(1 0.5) (4)(5000) (0.5)(4)(5000) 80, 000, 000, 000 Confidence Interval = 80, 000, , 000, 000,000 (77,47,388.51, 8,75,611.49)

1. The number of dental claims for each insured in a calendar year is distributed as a Geometric distribution with variance of

1. The number of dental claims for each insured in a calendar year is distributed as a Geometric distribution with variance of 1. The number of dental claims for each insured in a calendar year is distributed as a Geometric distribution with variance of 7.315. The amount of each claim is distributed as a Pareto distribution with

More information

1. The number of dental claims for each insured in a calendar year is distributed as a Geometric distribution with variance of

1. The number of dental claims for each insured in a calendar year is distributed as a Geometric distribution with variance of 1. The number of dental claims for each insured in a calendar year is distributed as a Geometric distribution with variance of 7.3125. The amount of each claim is distributed as a Pareto distribution with

More information

STAT 479 Test 2 Spring 2013

STAT 479 Test 2 Spring 2013 STAT 479 Test 2 Spring 2013 March 26, 2013 1. You have a sample 10 claims from a Pareto distribution. You are given that 10 X i 1 16,000,000. and 10 2 Xi i 1 i 12,000 Yi uses this information to determine

More information

**BEGINNING OF EXAMINATION** A random sample of five observations from a population is:

**BEGINNING OF EXAMINATION** A random sample of five observations from a population is: **BEGINNING OF EXAMINATION** 1. You are given: (i) A random sample of five observations from a population is: 0.2 0.7 0.9 1.1 1.3 (ii) You use the Kolmogorov-Smirnov test for testing the null hypothesis,

More information

Homework Problems Stat 479

Homework Problems Stat 479 Chapter 10 91. * A random sample, X1, X2,, Xn, is drawn from a distribution with a mean of 2/3 and a variance of 1/18. ˆ = (X1 + X2 + + Xn)/(n-1) is the estimator of the distribution mean θ. Find MSE(

More information

Homework Problems Stat 479

Homework Problems Stat 479 Chapter 2 1. Model 1 in the table handed out in class is a uniform distribution from 0 to 100. Determine what the table entries would be for a generalized uniform distribution covering the range from a

More information

Homework Problems Stat 479

Homework Problems Stat 479 Chapter 2 1. Model 1 is a uniform distribution from 0 to 100. Determine the table entries for a generalized uniform distribution covering the range from a to b where a < b. 2. Let X be a discrete random

More information

SYLLABUS OF BASIC EDUCATION SPRING 2018 Construction and Evaluation of Actuarial Models Exam 4

SYLLABUS OF BASIC EDUCATION SPRING 2018 Construction and Evaluation of Actuarial Models Exam 4 The syllabus for this exam is defined in the form of learning objectives that set forth, usually in broad terms, what the candidate should be able to do in actual practice. Please check the Syllabus Updates

More information

Practice Exam 1. Loss Amount Number of Losses

Practice Exam 1. Loss Amount Number of Losses Practice Exam 1 1. You are given the following data on loss sizes: An ogive is used as a model for loss sizes. Determine the fitted median. Loss Amount Number of Losses 0 1000 5 1000 5000 4 5000 10000

More information

STAT 472 Fall 2013 Test 2 October 31, 2013

STAT 472 Fall 2013 Test 2 October 31, 2013 STAT 47 Fall 013 Test October 31, 013 1. (6 points) Yifei who is (45) is receiving an annuity with payments of 5,000 at the beginning of each year. The annuity guarantees that payments will be made for

More information

Exam M Fall 2005 PRELIMINARY ANSWER KEY

Exam M Fall 2005 PRELIMINARY ANSWER KEY Exam M Fall 005 PRELIMINARY ANSWER KEY Question # Answer Question # Answer 1 C 1 E C B 3 C 3 E 4 D 4 E 5 C 5 C 6 B 6 E 7 A 7 E 8 D 8 D 9 B 9 A 10 A 30 D 11 A 31 A 1 A 3 A 13 D 33 B 14 C 34 C 15 A 35 A

More information

STAT 479 Test 3 Spring 2016 May 3, 2016

STAT 479 Test 3 Spring 2016 May 3, 2016 The final will be set as a case study. This means that you will be using the same set up for all the problems. It also means that you are using the same data for several problems. This should actually

More information

1. You are given the following information about a stationary AR(2) model:

1. You are given the following information about a stationary AR(2) model: Fall 2003 Society of Actuaries **BEGINNING OF EXAMINATION** 1. You are given the following information about a stationary AR(2) model: (i) ρ 1 = 05. (ii) ρ 2 = 01. Determine φ 2. (A) 0.2 (B) 0.1 (C) 0.4

More information

1. Datsenka Dog Insurance Company has developed the following mortality table for dogs: l x

1. Datsenka Dog Insurance Company has developed the following mortality table for dogs: l x 1. Datsenka Dog Insurance Company has developed the following mortality table for dogs: Age l Age 0 000 5 100 1 1950 6 1000 1850 7 700 3 1600 8 300 4 1400 9 0 l Datsenka sells an whole life annuity based

More information

Subject CS2A Risk Modelling and Survival Analysis Core Principles

Subject CS2A Risk Modelling and Survival Analysis Core Principles ` Subject CS2A Risk Modelling and Survival Analysis Core Principles Syllabus for the 2019 exams 1 June 2018 Copyright in this Core Reading is the property of the Institute and Faculty of Actuaries who

More information

Two hours. To be supplied by the Examinations Office: Mathematical Formula Tables and Statistical Tables THE UNIVERSITY OF MANCHESTER

Two hours. To be supplied by the Examinations Office: Mathematical Formula Tables and Statistical Tables THE UNIVERSITY OF MANCHESTER Two hours MATH20802 To be supplied by the Examinations Office: Mathematical Formula Tables and Statistical Tables THE UNIVERSITY OF MANCHESTER STATISTICAL METHODS Answer any FOUR of the SIX questions.

More information

1. For two independent lives now age 30 and 34, you are given:

1. For two independent lives now age 30 and 34, you are given: Society of Actuaries Course 3 Exam Fall 2003 **BEGINNING OF EXAMINATION** 1. For two independent lives now age 30 and 34, you are given: x q x 30 0.1 31 0.2 32 0.3 33 0.4 34 0.5 35 0.6 36 0.7 37 0.8 Calculate

More information

1. The probability that a visit to a primary care physician s (PCP) office results in neither

1. The probability that a visit to a primary care physician s (PCP) office results in neither 1. The probability that a visit to a primary care physician s (PCP) office results in neither lab work nor referral to a specialist is 35%. Of those coming to a PCP s office, 30% are referred to specialists

More information

UPDATED IAA EDUCATION SYLLABUS

UPDATED IAA EDUCATION SYLLABUS II. UPDATED IAA EDUCATION SYLLABUS A. Supporting Learning Areas 1. STATISTICS Aim: To enable students to apply core statistical techniques to actuarial applications in insurance, pensions and emerging

More information

SOCIETY OF ACTUARIES EXAM STAM SHORT-TERM ACTUARIAL MATHEMATICS EXAM STAM SAMPLE QUESTIONS

SOCIETY OF ACTUARIES EXAM STAM SHORT-TERM ACTUARIAL MATHEMATICS EXAM STAM SAMPLE QUESTIONS SOCIETY OF ACTUARIES EXAM STAM SHORT-TERM ACTUARIAL MATHEMATICS EXAM STAM SAMPLE QUESTIONS Questions 1-307 have been taken from the previous set of Exam C sample questions. Questions no longer relevant

More information

Gamma Distribution Fitting

Gamma Distribution Fitting Chapter 552 Gamma Distribution Fitting Introduction This module fits the gamma probability distributions to a complete or censored set of individual or grouped data values. It outputs various statistics

More information

Chapter 2 and 3 Exam Prep Questions

Chapter 2 and 3 Exam Prep Questions 1 You are given the following mortality table: q for males q for females 90 020 010 91 02 01 92 030 020 93 040 02 94 00 030 9 060 040 A life insurance company currently has 1000 males insured and 1000

More information

SOCIETY OF ACTUARIES/CASUALTY ACTUARIAL SOCIETY EXAM C CONSTRUCTION AND EVALUATION OF ACTUARIAL MODELS EXAM C SAMPLE QUESTIONS

SOCIETY OF ACTUARIES/CASUALTY ACTUARIAL SOCIETY EXAM C CONSTRUCTION AND EVALUATION OF ACTUARIAL MODELS EXAM C SAMPLE QUESTIONS SOCIETY OF ACTUARIES/CASUALTY ACTUARIAL SOCIETY EXAM C CONSTRUCTION AND EVALUATION OF ACTUARIAL MODELS EXAM C SAMPLE QUESTIONS Copyright 2008 by the Society of Actuaries and the Casualty Actuarial Society

More information

STAT 472 Fall 2016 Test 2 November 8, 2016

STAT 472 Fall 2016 Test 2 November 8, 2016 STAT 472 Fall 2016 Test 2 November 8, 2016 1. Anne who is (65) buys a whole life policy with a death benefit of 200,000 payable at the end of the year of death. The policy has annual premiums payable for

More information

**BEGINNING OF EXAMINATION**

**BEGINNING OF EXAMINATION** Fall 2002 Society of Actuaries **BEGINNING OF EXAMINATION** 1. Given: The survival function s x sbxg = 1, 0 x < 1 b g x d i { } b g, where s x = 1 e / 100, 1 x < 45. b g = s x 0, 4.5 x Calculate µ b4g.

More information

Summary of Formulae for Actuarial Life Contingencies

Summary of Formulae for Actuarial Life Contingencies Summary of Formulae for Actuarial Life Contingencies Contents Review of Basic Actuarial Functions... 3 Random Variables... 5 Future Lifetime (Continuous)... 5 Curtate Future Lifetime (Discrete)... 5 1/m

More information

Introduction to Business Statistics QM 120 Chapter 6

Introduction to Business Statistics QM 120 Chapter 6 DEPARTMENT OF QUANTITATIVE METHODS & INFORMATION SYSTEMS Introduction to Business Statistics QM 120 Chapter 6 Spring 2008 Chapter 6: Continuous Probability Distribution 2 When a RV x is discrete, we can

More information

Section Distributions of Random Variables

Section Distributions of Random Variables Section 8.1 - Distributions of Random Variables Definition: A random variable is a rule that assigns a number to each outcome of an experiment. Example 1: Suppose we toss a coin three times. Then we could

More information

Credibility. Chapters Stat Loss Models. Chapters (Stat 477) Credibility Brian Hartman - BYU 1 / 31

Credibility. Chapters Stat Loss Models. Chapters (Stat 477) Credibility Brian Hartman - BYU 1 / 31 Credibility Chapters 17-19 Stat 477 - Loss Models Chapters 17-19 (Stat 477) Credibility Brian Hartman - BYU 1 / 31 Why Credibility? You purchase an auto insurance policy and it costs $150. That price is

More information

8.5 Numerical Evaluation of Probabilities

8.5 Numerical Evaluation of Probabilities 8.5 Numerical Evaluation of Probabilities 1 Density of event individual became disabled at time t is so probability is tp 7µ 1 7+t 16 tp 11 7+t 16.3e.4t e.16 t dt.3e.3 16 Density of event individual became

More information

Changes to Exams FM/2, M and C/4 for the May 2007 Administration

Changes to Exams FM/2, M and C/4 for the May 2007 Administration Changes to Exams FM/2, M and C/4 for the May 2007 Administration Listed below is a summary of the changes, transition rules, and the complete exam listings as they will appear in the Spring 2007 Basic

More information

SOCIETY OF ACTUARIES. EXAM MLC Models for Life Contingencies EXAM MLC SAMPLE QUESTIONS. Copyright 2013 by the Society of Actuaries

SOCIETY OF ACTUARIES. EXAM MLC Models for Life Contingencies EXAM MLC SAMPLE QUESTIONS. Copyright 2013 by the Society of Actuaries SOCIETY OF ACTUARIES EXAM MLC Models for Life Contingencies EXAM MLC SAMPLE QUESTIONS Copyright 2013 by the Society of Actuaries The questions in this study note were previously presented in study note

More information

TOPIC: PROBABILITY DISTRIBUTIONS

TOPIC: PROBABILITY DISTRIBUTIONS TOPIC: PROBABILITY DISTRIBUTIONS There are two types of random variables: A Discrete random variable can take on only specified, distinct values. A Continuous random variable can take on any value within

More information

Section Distributions of Random Variables

Section Distributions of Random Variables Section 8.1 - Distributions of Random Variables Definition: A random variable is a rule that assigns a number to each outcome of an experiment. Example 1: Suppose we toss a coin three times. Then we could

More information

Can we use kernel smoothing to estimate Value at Risk and Tail Value at Risk?

Can we use kernel smoothing to estimate Value at Risk and Tail Value at Risk? Can we use kernel smoothing to estimate Value at Risk and Tail Value at Risk? Ramon Alemany, Catalina Bolancé and Montserrat Guillén Riskcenter - IREA Universitat de Barcelona http://www.ub.edu/riskcenter

More information

DISABILITY AND DEATH PROBABILITY TABLES FOR INSURED WORKERS BORN IN 1995

DISABILITY AND DEATH PROBABILITY TABLES FOR INSURED WORKERS BORN IN 1995 ACTUARIAL NOTE Number 2015.6 December 2015 SOCIAL SECURITY ADMINISTRATION Office of the Chief Actuary Baltimore, Maryland DISABILITY AND DEATH PROBABILITY TABLES FOR INSURED WORKERS BORN IN 1995 by Johanna

More information

INSTITUTE OF ACTUARIES OF INDIA EXAMINATIONS. 20 th May Subject CT3 Probability & Mathematical Statistics

INSTITUTE OF ACTUARIES OF INDIA EXAMINATIONS. 20 th May Subject CT3 Probability & Mathematical Statistics INSTITUTE OF ACTUARIES OF INDIA EXAMINATIONS 20 th May 2013 Subject CT3 Probability & Mathematical Statistics Time allowed: Three Hours (10.00 13.00) Total Marks: 100 INSTRUCTIONS TO THE CANDIDATES 1.

More information

Simulation Wrap-up, Statistics COS 323

Simulation Wrap-up, Statistics COS 323 Simulation Wrap-up, Statistics COS 323 Today Simulation Re-cap Statistics Variance and confidence intervals for simulations Simulation wrap-up FYI: No class or office hours Thursday Simulation wrap-up

More information

Download From:

Download From: INSTITUTE OF ACTUARIES OF INDIA EXAMINATIONS 12 th May 2010 Subject CT4 Models Time allowed: Three Hours (10.00 13.00 Hrs) Total Marks: 100 INSTRUCTIONS TO THE CANDIDATES 1) Please read the instructions

More information

Subject CS1 Actuarial Statistics 1 Core Principles. Syllabus. for the 2019 exams. 1 June 2018

Subject CS1 Actuarial Statistics 1 Core Principles. Syllabus. for the 2019 exams. 1 June 2018 ` Subject CS1 Actuarial Statistics 1 Core Principles Syllabus for the 2019 exams 1 June 2018 Copyright in this Core Reading is the property of the Institute and Faculty of Actuaries who are the sole distributors.

More information

Exam MLC Spring 2007 FINAL ANSWER KEY

Exam MLC Spring 2007 FINAL ANSWER KEY Exam MLC Spring 2007 FINAL ANSWER KEY Question # Answer Question # Answer 1 E 16 B 2 B 17 D 3 D 18 C 4 E 19 D 5 C 20 C 6 A 21 B 7 E 22 C 8 E 23 B 9 E 24 A 10 C 25 B 11 A 26 A 12 D 27 A 13 C 28 C 14 * 29

More information

PSTAT 172A: ACTUARIAL STATISTICS FINAL EXAM

PSTAT 172A: ACTUARIAL STATISTICS FINAL EXAM PSTAT 172A: ACTUARIAL STATISTICS FINAL EXAM March 17, 2009 This exam is closed to books and notes, but you may use a calculator. You have 3 hours. Your exam contains 7 questions and 11 pages. Please make

More information

3 3 Measures of Central Tendency and Dispersion from grouped data.notebook October 23, 2017

3 3 Measures of Central Tendency and Dispersion from grouped data.notebook October 23, 2017 Warm Up a. Determine the sample standard deviation weight. Express your answer rounded to three decimal places. b. Use the Empirical Rule to determine the percentage of M&Ms with weights between 0.803

More information

Measure of Variation

Measure of Variation Measure of Variation Variation is the spread of a data set. The simplest measure is the range. Range the difference between the maximum and minimum data entries in the set. To find the range, the data

More information

Chapter 4: Commonly Used Distributions. Statistics for Engineers and Scientists Fourth Edition William Navidi

Chapter 4: Commonly Used Distributions. Statistics for Engineers and Scientists Fourth Edition William Navidi Chapter 4: Commonly Used Distributions Statistics for Engineers and Scientists Fourth Edition William Navidi 2014 by Education. This is proprietary material solely for authorized instructor use. Not authorized

More information

Teachers Pension and Annuity Fund of New Jersey. Experience Study July 1, 2006 June 30, 2009

Teachers Pension and Annuity Fund of New Jersey. Experience Study July 1, 2006 June 30, 2009 Teachers Pension and Annuity Fund of New Jersey Experience Study July 1, 2006 June 30, 2009 by Richard L. Gordon Scott F. Porter December, 2010 TABLE OF CONTENTS PAGE SECTION I EXECUTIVE SUMMARY 1 INTRODUCTION

More information

Monte Carlo Methods in Financial Engineering

Monte Carlo Methods in Financial Engineering Paul Glassennan Monte Carlo Methods in Financial Engineering With 99 Figures

More information

Unit 04 Review. Probability Rules

Unit 04 Review. Probability Rules Unit 04 Review Probability Rules A sample space contains all the possible outcomes observed in a trial of an experiment, a survey, or some random phenomenon. The sum of the probabilities for all possible

More information

Point Estimation. Stat 4570/5570 Material from Devore s book (Ed 8), and Cengage

Point Estimation. Stat 4570/5570 Material from Devore s book (Ed 8), and Cengage 6 Point Estimation Stat 4570/5570 Material from Devore s book (Ed 8), and Cengage Point Estimation Statistical inference: directed toward conclusions about one or more parameters. We will use the generic

More information

A. 11 B. 15 C. 19 D. 23 E. 27. Solution. Let us write s for the policy year. Then the mortality rate during year s is q 30+s 1.

A. 11 B. 15 C. 19 D. 23 E. 27. Solution. Let us write s for the policy year. Then the mortality rate during year s is q 30+s 1. Solutions to the Spring 213 Course MLC Examination by Krzysztof Ostaszewski, http://wwwkrzysionet, krzysio@krzysionet Copyright 213 by Krzysztof Ostaszewski All rights reserved No reproduction in any form

More information

STA 103: Final Exam. Print clearly on this exam. Only correct solutions that can be read will be given credit.

STA 103: Final Exam. Print clearly on this exam. Only correct solutions that can be read will be given credit. STA 103: Final Exam June 26, 2008 Name: } {{ } by writing my name i swear by the honor code Read all of the following information before starting the exam: Print clearly on this exam. Only correct solutions

More information

Catholic Health East Employee Pension Plan. Summary Plan Description Supplement Effective January 1, 2017

Catholic Health East Employee Pension Plan. Summary Plan Description Supplement Effective January 1, 2017 Catholic Health East Employee Pension Plan Summary Plan Description Supplement Effective January 1, 2017 St. Peter s Hospital of the City of Albany Plan Participants 1. Employer For purposes of this supplement,

More information

AP Statistics Chapter 6 - Random Variables

AP Statistics Chapter 6 - Random Variables AP Statistics Chapter 6 - Random 6.1 Discrete and Continuous Random Objective: Recognize and define discrete random variables, and construct a probability distribution table and a probability histogram

More information

PSTAT 172A: ACTUARIAL STATISTICS FINAL EXAM

PSTAT 172A: ACTUARIAL STATISTICS FINAL EXAM PSTAT 172A: ACTUARIAL STATISTICS FINAL EXAM March 19, 2008 This exam is closed to books and notes, but you may use a calculator. You have 3 hours. Your exam contains 9 questions and 13 pages. Please make

More information

SOCIETY OF ACTUARIES/CASUALTY ACTUARIAL SOCIETY EXAM P PROBABILITY EXAM P SAMPLE QUESTIONS

SOCIETY OF ACTUARIES/CASUALTY ACTUARIAL SOCIETY EXAM P PROBABILITY EXAM P SAMPLE QUESTIONS SOCIETY OF ACTUARIES/CASUALTY ACTUARIAL SOCIETY EXAM P PROBABILITY EXAM P SAMPLE QUESTIONS Copyright 007 by the Society of Actuaries and the Casualty Actuarial Society Some of the questions in this study

More information

2017 IAA EDUCATION SYLLABUS

2017 IAA EDUCATION SYLLABUS 2017 IAA EDUCATION SYLLABUS 1. STATISTICS Aim: To enable students to apply core statistical techniques to actuarial applications in insurance, pensions and emerging areas of actuarial practice. 1.1 RANDOM

More information

Section 7.5 The Normal Distribution. Section 7.6 Application of the Normal Distribution

Section 7.5 The Normal Distribution. Section 7.6 Application of the Normal Distribution Section 7.6 Application of the Normal Distribution A random variable that may take on infinitely many values is called a continuous random variable. A continuous probability distribution is defined by

More information

MATH 3630 Actuarial Mathematics I Class Test 1-3:35-4:50 PM Wednesday, 15 November 2017 Time Allowed: 1 hour and 15 minutes Total Marks: 100 points

MATH 3630 Actuarial Mathematics I Class Test 1-3:35-4:50 PM Wednesday, 15 November 2017 Time Allowed: 1 hour and 15 minutes Total Marks: 100 points MATH 3630 Actuarial Mathematics I Class Test 1-3:35-4:50 PM Wednesday, 15 November 2017 Time Allowed: 1 hour and 15 minutes Total Marks: 100 points Please write your name and student number at the spaces

More information

Chapter 5 Discrete Probability Distributions. Random Variables Discrete Probability Distributions Expected Value and Variance

Chapter 5 Discrete Probability Distributions. Random Variables Discrete Probability Distributions Expected Value and Variance Chapter 5 Discrete Probability Distributions Random Variables Discrete Probability Distributions Expected Value and Variance.40.30.20.10 0 1 2 3 4 Random Variables A random variable is a numerical description

More information

INSTITUTE AND FACULTY OF ACTUARIES. Curriculum 2019 SPECIMEN EXAMINATION

INSTITUTE AND FACULTY OF ACTUARIES. Curriculum 2019 SPECIMEN EXAMINATION INSTITUTE AND FACULTY OF ACTUARIES Curriculum 2019 SPECIMEN EXAMINATION Subject CS1A Actuarial Statistics Time allowed: Three hours and fifteen minutes INSTRUCTIONS TO THE CANDIDATE 1. Enter all the candidate

More information

Statistical analysis and bootstrapping

Statistical analysis and bootstrapping Statistical analysis and bootstrapping p. 1/15 Statistical analysis and bootstrapping Michel Bierlaire michel.bierlaire@epfl.ch Transport and Mobility Laboratory Statistical analysis and bootstrapping

More information

STAT 509: Statistics for Engineers Dr. Dewei Wang. Copyright 2014 John Wiley & Sons, Inc. All rights reserved.

STAT 509: Statistics for Engineers Dr. Dewei Wang. Copyright 2014 John Wiley & Sons, Inc. All rights reserved. STAT 509: Statistics for Engineers Dr. Dewei Wang Applied Statistics and Probability for Engineers Sixth Edition Douglas C. Montgomery George C. Runger 7 Point CHAPTER OUTLINE 7-1 Point Estimation 7-2

More information

Discrete probability distributions

Discrete probability distributions Discrete probability distributions Probability distributions Discrete random variables Expected values (mean) Variance Linear functions - mean & standard deviation Standard deviation 1 Probability distributions

More information

Financial Econometrics (FinMetrics04) Time-series Statistics Concepts Exploratory Data Analysis Testing for Normality Empirical VaR

Financial Econometrics (FinMetrics04) Time-series Statistics Concepts Exploratory Data Analysis Testing for Normality Empirical VaR Financial Econometrics (FinMetrics04) Time-series Statistics Concepts Exploratory Data Analysis Testing for Normality Empirical VaR Nelson Mark University of Notre Dame Fall 2017 September 11, 2017 Introduction

More information

MODELS FOR QUANTIFYING RISK

MODELS FOR QUANTIFYING RISK MODELS FOR QUANTIFYING RISK THIRD EDITION ROBIN J. CUNNINGHAM, FSA, PH.D. THOMAS N. HERZOG, ASA, PH.D. RICHARD L. LONDON, FSA B 360811 ACTEX PUBLICATIONS, INC. WINSTED, CONNECTICUT PREFACE iii THIRD EDITION

More information

MATH 3200 Exam 3 Dr. Syring

MATH 3200 Exam 3 Dr. Syring . Suppose n eligible voters are polled (randomly sampled) from a population of size N. The poll asks voters whether they support or do not support increasing local taxes to fund public parks. Let M be

More information

Random Variables Handout. Xavier Vilà

Random Variables Handout. Xavier Vilà Random Variables Handout Xavier Vilà Course 2004-2005 1 Discrete Random Variables. 1.1 Introduction 1.1.1 Definition of Random Variable A random variable X is a function that maps each possible outcome

More information

INSTRUCTIONS TO CANDIDATES

INSTRUCTIONS TO CANDIDATES Society of Actuaries Canadian Institute of Actuaries Exam MLC Models for Life Contingencies Tuesday, April 25, 2017 8:30 a.m. 12:45 p.m. MLC General Instructions 1. Write your candidate number here. Your

More information

1. The force of mortality at age x is given by 10 µ(x) = 103 x, 0 x < 103. Compute E(T(81) 2 ]. a. 7. b. 22. c. 23. d. 20

1. The force of mortality at age x is given by 10 µ(x) = 103 x, 0 x < 103. Compute E(T(81) 2 ]. a. 7. b. 22. c. 23. d. 20 1 of 17 1/4/2008 12:01 PM 1. The force of mortality at age x is given by 10 µ(x) = 103 x, 0 x < 103. Compute E(T(81) 2 ]. a. 7 b. 22 3 c. 23 3 d. 20 3 e. 8 2. Suppose 1 for 0 x 1 s(x) = 1 ex 100 for 1

More information

PROBABILITY. Wiley. With Applications and R ROBERT P. DOBROW. Department of Mathematics. Carleton College Northfield, MN

PROBABILITY. Wiley. With Applications and R ROBERT P. DOBROW. Department of Mathematics. Carleton College Northfield, MN PROBABILITY With Applications and R ROBERT P. DOBROW Department of Mathematics Carleton College Northfield, MN Wiley CONTENTS Preface Acknowledgments Introduction xi xiv xv 1 First Principles 1 1.1 Random

More information

Group Anw gap insurance A surviving dependant s pension insurance for your partner May 2017

Group Anw gap insurance A surviving dependant s pension insurance for your partner May 2017 Group Anw gap insurance A surviving dependant s pension insurance for your partner May 2017 Elips Life Ltd, Dutch branch, Startbaan 8, NL-1185 XR Amstelveen; CR: 51782987; Statutory seat of Elips Life

More information

Mathematical Methods: Practice Problem Solving Task - Probability

Mathematical Methods: Practice Problem Solving Task - Probability Mathematical Methods: Practice Problem Solving Task - Probability Question 1 refers to the following graph The following graph shows the probabilities of the 5 outcomes (1 to 5) from a spinner, with one

More information

درس هفتم یادگیري ماشین. (Machine Learning) دانشگاه فردوسی مشهد دانشکده مهندسی رضا منصفی

درس هفتم یادگیري ماشین. (Machine Learning) دانشگاه فردوسی مشهد دانشکده مهندسی رضا منصفی یادگیري ماشین توزیع هاي نمونه و تخمین نقطه اي پارامترها Sampling Distributions and Point Estimation of Parameter (Machine Learning) دانشگاه فردوسی مشهد دانشکده مهندسی رضا منصفی درس هفتم 1 Outline Introduction

More information

The following content is provided under a Creative Commons license. Your support

The following content is provided under a Creative Commons license. Your support MITOCW Recitation 6 The following content is provided under a Creative Commons license. Your support will help MIT OpenCourseWare continue to offer high quality educational resources for free. To make

More information

3. Joyce needs to gather data that can be modeled with a linear function. Which situation would give Joyce the data she needs?

3. Joyce needs to gather data that can be modeled with a linear function. Which situation would give Joyce the data she needs? Unit 6 Assessment: Linear Models and Tables Assessment 8 th Grade Math 1. Which equation describes the line through points A and B? A. x 3y = -5 B. x + 3y = -5 C. x + 3y = 7 D. 3x + y = 5 2. The table

More information

Assignment 3-Solutions

Assignment 3-Solutions Assignment 3-Solutions Question 1. - Joint Probability Mass Function Consider the function x y 1.0 1.0 1.5 2.0 1.5 3.0 2.5 4.0 3.0 4.0 Determine the following: (a) Show that If is a valid probability mass

More information

A Comprehensive, Non-Aggregated, Stochastic Approach to. Loss Development

A Comprehensive, Non-Aggregated, Stochastic Approach to. Loss Development A Comprehensive, Non-Aggregated, Stochastic Approach to Loss Development By Uri Korn Abstract In this paper, we present a stochastic loss development approach that models all the core components of the

More information

Problem # 2. In a country with a large population, the number of persons, N, that are HIV positive at time t is given by:

Problem # 2. In a country with a large population, the number of persons, N, that are HIV positive at time t is given by: Problem # 1 A marketing survey indicates that 60% of the population owns an automobile, 30% owns a house, and 20% owns both an automobile and a house. Calculate the probability that a person chosen at

More information

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Exam Name MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Find a z-score satisfying the given condition. 1) 20.1% of the total area is to the right

More information

Point Estimation. Edwin Leuven

Point Estimation. Edwin Leuven Point Estimation Edwin Leuven Introduction Last time we reviewed statistical inference We saw that while in probability we ask: given a data generating process, what are the properties of the outcomes?

More information

Test 1 STAT Fall 2014 October 7, 2014

Test 1 STAT Fall 2014 October 7, 2014 Test 1 STAT 47201 Fall 2014 October 7, 2014 1. You are given: Calculate: i. Mortality follows the illustrative life table ii. i 6% a. The actuarial present value for a whole life insurance with a death

More information

Contents Part I Descriptive Statistics 1 Introduction and Framework Population, Sample, and Observations Variables Quali

Contents Part I Descriptive Statistics 1 Introduction and Framework Population, Sample, and Observations Variables Quali Part I Descriptive Statistics 1 Introduction and Framework... 3 1.1 Population, Sample, and Observations... 3 1.2 Variables.... 4 1.2.1 Qualitative and Quantitative Variables.... 5 1.2.2 Discrete and Continuous

More information

Module 3: Sampling Distributions and the CLT Statistics (OA3102)

Module 3: Sampling Distributions and the CLT Statistics (OA3102) Module 3: Sampling Distributions and the CLT Statistics (OA3102) Professor Ron Fricker Naval Postgraduate School Monterey, California Reading assignment: WM&S chpt 7.1-7.3, 7.5 Revision: 1-12 1 Goals for

More information

Chapter 7 1. Random Variables

Chapter 7 1. Random Variables Chapter 7 1 Random Variables random variable numerical variable whose value depends on the outcome of a chance experiment - discrete if its possible values are isolated points on a number line - continuous

More information

Section 8.1 Distributions of Random Variables

Section 8.1 Distributions of Random Variables Section 8.1 Distributions of Random Variables Random Variable A random variable is a rule that assigns a number to each outcome of a chance experiment. There are three types of random variables: 1. Finite

More information

Probability is the tool used for anticipating what the distribution of data should look like under a given model.

Probability is the tool used for anticipating what the distribution of data should look like under a given model. AP Statistics NAME: Exam Review: Strand 3: Anticipating Patterns Date: Block: III. Anticipating Patterns: Exploring random phenomena using probability and simulation (20%-30%) Probability is the tool used

More information

Actuarial Mathematics and Statistics Statistics 5 Part 2: Statistical Inference Tutorial Problems

Actuarial Mathematics and Statistics Statistics 5 Part 2: Statistical Inference Tutorial Problems Actuarial Mathematics and Statistics Statistics 5 Part 2: Statistical Inference Tutorial Problems Spring 2005 1. Which of the following statements relate to probabilities that can be interpreted as frequencies?

More information

MATH/STAT 4720, Life Contingencies II Fall 2015 Toby Kenney

MATH/STAT 4720, Life Contingencies II Fall 2015 Toby Kenney MATH/STAT 4720, Life Contingencies II Fall 2015 Toby Kenney In Class Examples () September 2, 2016 1 / 145 8 Multiple State Models Definition A Multiple State model has several different states into which

More information

INSTRUCTIONS TO CANDIDATES

INSTRUCTIONS TO CANDIDATES Society of Actuaries Canadian Institute of Actuaries Exam MLC Models for Life Contingencies Friday, October 30, 2015 8:30 a.m. 12:45 p.m. MLC General Instructions 1. Write your candidate number here. Your

More information

Name: CS3130: Probability and Statistics for Engineers Practice Final Exam Instructions: You may use any notes that you like, but no calculators or computers are allowed. Be sure to show all of your work.

More information

4.1 Probability Distributions

4.1 Probability Distributions Probability and Statistics Mrs. Leahy Chapter 4: Discrete Probability Distribution ALWAYS KEEP IN MIND: The Probability of an event is ALWAYS between: and!!!! 4.1 Probability Distributions Random Variables

More information

MANAGEMENT PRINCIPLES AND STATISTICS (252 BE)

MANAGEMENT PRINCIPLES AND STATISTICS (252 BE) MANAGEMENT PRINCIPLES AND STATISTICS (252 BE) Normal and Binomial Distribution Applied to Construction Management Sampling and Confidence Intervals Sr Tan Liat Choon Email: tanliatchoon@gmail.com Mobile:

More information

M.Sc. ACTUARIAL SCIENCE. Term-End Examination

M.Sc. ACTUARIAL SCIENCE. Term-End Examination No. of Printed Pages : 15 LMJA-010 (F2F) M.Sc. ACTUARIAL SCIENCE Term-End Examination O CD December, 2011 MIA-010 (F2F) : STATISTICAL METHOD Time : 3 hours Maximum Marks : 100 SECTION - A Attempt any five

More information

Exam P Flashcards exams. Key concepts. Important formulas. Efficient methods. Advice on exam technique

Exam P Flashcards exams. Key concepts. Important formulas. Efficient methods. Advice on exam technique Exam P Flashcards 01 exams Key concepts Important formulas Efficient methods Advice on exam technique All study material produced by BPP Professional Education is copyright and is sold for the exclusive

More information

Surrenders in a competing risks framework, application with the [FG99] model

Surrenders in a competing risks framework, application with the [FG99] model s in a competing risks framework, application with the [FG99] model AFIR - ERM - LIFE Lyon Colloquia June 25 th, 2013 1,2 Related to a joint work with D. Seror 1 and D. Nkihouabonga 1 1 ENSAE ParisTech,

More information

1. For a special whole life insurance on (x), payable at the moment of death:

1. For a special whole life insurance on (x), payable at the moment of death: **BEGINNING OF EXAMINATION** 1. For a special whole life insurance on (x), payable at the moment of death: µ () t = 0.05, t > 0 (ii) δ = 0.08 x (iii) (iv) The death benefit at time t is bt 0.06t = e, t

More information

Exam STAM Practice Exam #1

Exam STAM Practice Exam #1 !!!! Exam STAM Practice Exam #1 These practice exams should be used during the month prior to your exam. This practice exam contains 20 questions, of equal value, corresponding to about a 2 hour exam.

More information

RANCHO CALIFORNIA WATER DISTRICT Employee Policy & Procedure Manual

RANCHO CALIFORNIA WATER DISTRICT Employee Policy & Procedure Manual 1.0 POLICY The District has contracted with the California Public Employees Retirement System (CalPERS) in order to provide employees with retirement and other benefits. The District s retirement program

More information

Continuous Probability Distributions & Normal Distribution

Continuous Probability Distributions & Normal Distribution Mathematical Methods Units 3/4 Student Learning Plan Continuous Probability Distributions & Normal Distribution 7 lessons Notes: Students need practice in recognising whether a problem involves a discrete

More information

Dan Sherman, ASA, MAAA Sherman Actuarial Services, LLC

Dan Sherman, ASA, MAAA Sherman Actuarial Services, LLC Dan Sherman, ASA, MAAA Sherman Actuarial Services, LLC www.shermanactuary.com Forecast of future events Events (partial list) Retirement Termination Disability (Accidental versus Ordinary) Death Investment

More information