CHAPTER 5 ELEMENTARY STOCHASTIC CALCULUS. In all of these X(t) is Brownian motion. 1. By considering X 2 (t), show that
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1 CHAPTER 5 ELEMENTARY STOCHASTIC CALCULUS In all of these X(t is Brownian motion. 1. By considering X (t, show that X(τdX(τ = 1 X (t 1 t. We use Itô s Lemma for a function F(X(t: Note that df = df dx dx + 1 d F dx dt. df = [F ] t, and let F = X (t. Then df = X (t X ( = X (t, as X( =. Applying Itô s Lemma to F gives us that df = XdX + dt, (X(τdX(τ + dτ = X (t.. Show that X(τdX(τ = 1 X 1 t. τdx(τ = tx(t X(τdτ.
2 4 ELEMENTARY STOCHASTIC CALCULUS We use Itô s Lemma for a function F(X(t,t: df = df ( df dx dx d F dt dx dt. Let F = tx(t. Then df = tx(t. Applying Itô s Lemma to F gives us that df = tdx + Xdt, (τdx(τ + X(τdτ = tx(t. τdx(τ = tx(t X(τdτ. 3. Show that X (τ dx(τ = 1 3 X3 (t X(τdτ. Let F = X 3 (t. Then df = X 3 (t X 3 ( = X 3 (t, as X( =. Applying Itô s Lemma to F gives us that df = 3X dx + 3Xdt, (3X (τ dx(τ + 3X(τdτ = X 3 (t. X (τ dx(τ = 1 3 X3 X(τdτ. 4. Consider a function f(t which is continuous and bounded on [,t]. Prove integration by parts, i.e. f(τdx(τ= f(tx(t X(τ df (τ.
3 INSTRUCTOR S MANUAL 5 Let F = f(tx(t. Then df = f(tx(t f(x( = f(tx(t. Applying Itô s Lemma to F gives us that df = fdx+ Xdf, (f (τ dx(τ + X(τ df (τ = f(tx(t. f(τdx(τ= f(tx(t 5. Find u(w, t and v(w,t where dw(t = udt+ vdx(t X(τ df (τ. and (a W(t = X (t, (b W(t = 1 + t + e X(t, (c W(t = f(tx(t, where f is a bounded, continuous function. We use Itô s Lemma for a function W(X(t,t: dw = dw ( dw dx dx d W dt dx dt. (a (b Therefore dw = XdX+ dt = WdX+ dt. u(w, t = W and v(w,t = 1. dw = e X(t dx + ( 1 + e X(t dt. Rearranging the formula for W(t,we find that e X(t = W(t 1 t,
4 6 ELEMENTARY STOCHASTIC CALCULUS (c and so Therefore dw = (W(t 1 tdx + (W(t tdt. u(w, t = W(t 1 t and v(w,t = W(t t. dw = fdx+ X df dt dt. Therefore u(w, t = f(t and v(w,t = W(t df f(t dt. 6. If S follows a lognormal random walk, Use Itô s lemma to find the differential equations satisfied by (a f(s= AS + B, (b g(s = S n, (c h(s, t = S n e mt, where A, B and n are constants. Itô s lemma for a function f(s is df = σs df ds dx + ( µs df ds + 1 σ S d f ds dt. Then (a df = Aσ SdX + AµSdt = AdS. (b dg = nσ S n dx + ns n ( µ + 1 (n 1σ dt. (c dh = nσ S n e mt dx + S n e mt ( m + nµ + 1 n(n 1σ dt. 7. If ds = µs dt + σs dx, use Itô s lemma to find the stochastic differential equation satisfied by f(s= log(s. Itô s lemma for a function f(s is df = σs df ( ds dx + µs df ds + 1 σ S d f ds dt. Now df ds = 1/S and d f ds = 1/S, so df = σdx+ ( µ 1 σ dt.
5 INSTRUCTOR S MANUAL 7 Note that this stochastic differential equation for log(s has constant coefficients. For this reason, S is described as satisfying a lognormal random walk. 8. The change in a share price satisfies ds = A(S, tdx + B(S,tdt, for some functions A, B, what is the stochastic differential equation satisfied by f(s,t? Can A, B be chosen so that a function g(s has a zero drift, but non-zero variance? We could use Itô s Lemma directly to answer this and the following question, but as a teaching aid, will derive the results informally from first principles. We apply Taylor s theorem to find the change in f over a small time step, f(s+ δs,t + δt: f(s+ δs,t + δt = f(s,t+ δs + S t δt + 1 f S δs + f S t δsδt + 1 f t δt +... Substitute for δs = σsδx+ µsδt to get δf = (AδX + Bδt + δt S t + 1 (A δx + B δt + ABδXδt f S δs + (AδXδt + Bδt f S t + 1 δt f t +... Discarding terms of O ( δt 3/ and smaller, δf = A S δx + ( B S + t δt + 1 A f S δx + O ( δt 3/. As δt, replace δt by dt, δx by dx and δx by dt to find the stochastic differential equation satisfied by f(s,t: df = A ( S dx + B S + 1 A f S + dt. t A function g(s will therefore satisfy the equation dg = A dg ( ds dx + B dg ds + 1 A d g ds dt.
6 8 ELEMENTARY STOCHASTIC CALCULUS For g(s to have a zero drift but non-zero variance, we require that B dg ds + 1 A d g ds =. We can find a solution to this problem if A /B is independent of time. 9. Two shares follow geometric Brownian motions, i.e. ds 1 = µ 1 S 1 dt + σ 1 S 1 dx 1, ds = µ S dt + σ S dx, The share price changes are correlated with correlation coefficient ρ. Find the stochastic differential equation satisfied by a function f(s 1,S. We apply Taylor s theorem to find the change in f over a small time step - f(s 1 + δs 1,S + δs : f(s 1 + δs 1,S + δs = f(s+ δs 1 + δs + 1 f S 1 S δs 1 S 1 f + δs 1 δs + 1 f S 1 S δs S +... Substituting for δs 1 and δs, and discarding terms of O ( δt 3/ and smaller, we find that δf = σ 1 S 1 δx 1 + σ S δx + µ 1 S 1 δt + µ S δt S 1 S S 1 S + 1 σ 1 f S 1 S δx σ f S 1 S δx f + σ 1 σ S 1 S δx 1 δx + O ( δt 3/. S 1 S As δt, replace δt by dt, δx 1 by dx1, δx by dx, δx1 by dt, δx by dt and δx 1δX by ρdt to find the stochastic differential equation satisfied by f(s 1,S : df = σ 1 S 1 dx 1 + σ S dx S 1 S ( + µ 1 S 1 + µ S + 1 S 1 S σ f 1 S 1 S + 1 σ f S 1 S + ρσ 1 σ S 1 S f S 1 S dt.
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