Noninstantaneous Replenishment

Transcription

1 D Special Inventory Models PowerPoint Slides by Jeff Heyl For Operations Management, 9e by Krajewski/Ritzman/Malhotra 010 Pearson Education D 1 Noninstantaneous Replenishment Maximum cycle inventory Item used or sold as it is completed Usually production rate, p, exceeds the demand rate, d, so there is a buildup of (p d) units per time period Both p and d expressed in same time interval Buildup continues for /p days D 1

2 Noninstantaneous Replenishment On-hand inventor ry I max p d Production quantity Demand during production interval Maximum inventory Production and demand Demand only TBO Time Figure D.1 Lot Sizing with Noninstantaneous Replenishment D 3 Noninstantaneous Replenishment Maximum cycle inventory is: I max p p d p p d where p = production rate d = demand rate = lot size Cycle inventory is no longer /, it is I max / D 4

3 Noninstantaneous Replenishment Total annual cost = Annual holding cost + Annual ordering or setup cost D is annual demand and is lot size d is daily demand; p is daily production rate C I max D p d p D H S H S D 5 Noninstantaneous Replenishment Economic Production Lot Size (ELS): optimal lot size Derived by calculus Because the second term is greater than 1, the ELS results in a larger lot size than the EO ELS DS H p p d D 6 3

4 Finding the Economic Production Lot Size EXAMPLE D.1 A plant manager of a chemical plant must determine the lot size for a particular chemical that has a steady demand of 30 barrels per day. The production rate is 190 barrels per day, annual demand is 10,500 barrels, setup cost is $00, annual holding cost is $0.1 per barrel, and the plant operates 350 days per year. a. Determine the economic production lot size (ELS) b. Determine the total annual setup and inventory holding cost for this item c. Determine the time between orders (TBO), or cycle length, for the ELS d. Determine the production time per lot What are the advantages of reducing the setup time by 10 percent? D 7 Finding the Economic Production Lot Size SOLUTION a. Solving first for the ELS, we get DS p ELS H p d 10, 500$ 00 $ ,873.4 barrels b. The total annual cost with the ELS is p d C p D H S 4, $ $ $ , 500 4, $ 0. 1 $ 00 D 8 4

5 Finding the Economic Production Lot Size c. Applying the TBO formula to the ELS, we get TBO ELS ELS D 350 days/year 4, , or 16 days d. The production time during each cycle is the lot size divided by the production rate: ELS p 4, or 6 days D 9 Finding the Economic Production Lot Size Figure D. OM Explorer Solver for the Economic Production Lot Size Showing the Effect of a 10 Percent Reduction in Setup Cost D 10 5

6 Application D.1 A domestic automobile manufacturer schedules 1 two-person teams to assemble 4.6 liter DOHC V-8 engines per work day. Each team can assemble 5 engines per day. The automobile final assembly line creates an annual demand d for the DOHC engine at 10,080 units per year. The engine and automobile assembly plants operate 6 days per week, 48 weeks per year. The engine assembly line also produces SOHC V-8 engines. The cost to switch the production line from one type of engine to the other is $100,000. It costs $,000 to store one DOHC V-8 for one year. a. What is the economic lot size? b. How long is the production run? c. What is the average quantity in inventory? d. What is the total annual cost? D 11 Application D.1 SOLUTION a. Demand per day = d = 10,080/[(48)(6)] = 35 DS ELS H p p d 10, , 000, , or 1,555 engines b. The production run 1555, 5.91 or p 60 6 production days D 1 6

7 Application D.1 c. Average inventory I max p d 1555, engines p 60 d. Total annual cost I C max D p d p D H S H S 1555, $ 647, 917 $ 648, 31 $ 196,, , , $, 000 $ 100, 000 D 13 uantity Discounts Price incentives to purchase large quantities create pressure to maintain a large inventory Item s price is no longer fixed If the order quantity is increased enough, then the price per unit is discounted A new approach is needed to find the best lot size that balances: Advantages of lower prices for purchased materials and fewer orders Disadvantages of the increased cost of holding more inventory D 14 7

8 uantity Discounts Total annual cost = Annual holding cost + Annual ordering or setup cost + Annual cost of materials C D H S PD where P = price per unit D 15 uantity Discounts Unit holding cost (H) is usually expressed as a percentage of unit price The lower the unit price (P) is, the lower the unit holding cost (H) is The total cost equation yields U-shape total cost curves There are cost curves for each price level The feasible total cost begins with the top curve, then drops down, curve by curve, at the price breaks EOs do not necessarily produce the best lot size The EO at a particular price level may not be feasible The EO at a particular price level may be feasible but may not be the best lot size D 16 8

9 Two-Step Solution Procedure Step 1. Beginning with lowest price, calculate the EO for each price level until a feasible EO is found. It is feasible if it lies in the range corresponding to its price. Each subsequent EO is smaller than the previous one, because P, and thus H, gets larger and because the larger H is in the denominator of the EO formula. Step. If the first feasible EO found is for the lowest price level, this quantity is the best lot size. Otherwise, calculate the total cost for the first feasible EO and for the larger price break quantity at each lower price level. The quantity with the lowest total cost is optimal. D 17 uantity Discounts C for P = $4.00 C for P = $3.50 C for P = $3.00 EO 4.00 EO 3.50 EO 3.00 Total cost (dollars) PD for P = $4.00 PD for P = $3.50 PD for P = $3.00 Total cost (dollars) First price break Second price break First price break Second price break Purchase quantity () (a) Total cost curves with purchased materials added Purchase quantity () (b) EOs and price break quantities Figure D.3 Total Cost Curves with uantity Discounts D 18 9

10 Find with uantity Discounts EXAMPLE D. A supplier for St. LeRoy Hospital has introduced quantity discounts to encourage larger order quantities of a special catheter. The price schedule is Order uantity Price per Unit 0 to 99 $ to 499 $ or more $57.00 The hospital estimates that its annual demand for this item is 936 units, its ordering cost is $45.00 per order, and its annual holding cost is 5 percent of the catheter s unit price. What quantity of this catheter should the hospital order to minimize total costs? Suppose the price for quantities between 300 and 499 is reduced to $ Should the order quantity change? D 19 Find with uantity Discounts SOLUTION Step 1: Find the first feasible EO, starting with the lowest price level: DS 936$ H 0. 5$ EO units A 77-unit order actually costs $60.00 per unit, instead of the $57.00 per unit used in the EO calculation, so this EO is infeasible. Now try the $58.80 level: DS 936$ H 0. 5$ EO units This quantity also is infeasible because a 76-unit order is too small to qualify for the $58.80 price. Try the highest price level: D 0 10

11 Find with uantity Discounts DS 936$ H 0. 5 $ EO units This quantity is feasible because it lies in the range corresponding to its price, P = $60.00 Step : The first feasible EO of 75 does not correspond to the lowest price level. Hence, we must compare its total cost with the price break quantities (300 and 500 units) at the lower price levels ($58.80 and $57.00): D 1 Find with uantity Discounts C C C C 75 D H S PD $ $ $ $ , $ $ $ $ , $ $ $ $ , The best purchase quantity is 500 units, which qualifies for the deepest discount D 11

12 Find with uantity Discounts Figure D.4 OM Explorer Solver for uantity Discounts Showing the Best Order uantity D 3 Application D. A supplier s price schedule is: Order uantity Price per Unit 0 99 $ or more $45 If ordering cost is $16 per order, annual holding cost is 0 percent of the purchase price, and annual demand is 1,800 items, what is the best order quantity? D 4 1

13 Application D. SOLUTION Step 1: DS 1800, H 450. EO 00 DS 1800, H 500. EO units (infeasible) 76 units (feasible) Step : , C , $ 90, , C , $ 81, The best order quantity is 100 units D 5 One-Period Decisions Seasonal goods are a dilemma facing many retailers. Newsboy problem Step 1: List different demand levels and probabilities. Step : Develop a payoff table that shows the profit for each purchase quantity,, at each assumed demand level, D. Each row represents a different order quantity and each column represents a different demand. The payoff depends on whether all units are sold at the regular profit margin which results in two possible cases. D 6 13

14 One-Period Decisions If demand is high enough ( D), then all of the cases are sold at the full profit margin, p, during the regular season Payoff = (Profit per unit)(purchase quantity) = p If the purchase quantity exceeds the eventual demand ( > D), only D units are sold at the full profit margin, and the remaining units purchased must be disposed of at a loss, l, after the season Profit per Payoff = unit sold during (Demand) season Loss per unit Amount disposed of after season D 7 One-Period Decisions Step 3: Calculate the expected payoff of each by using the expected value decision rule. For a specific, first multiply each payoff by its demand probability, and then add the products. Step 4: Choose the order quantity with the highest expected payoff. D 8 14

15 Finding for One-Period Decisions EXAMPLE D.3 One of many items sold at a museum of natural history is a Christmas ornament carved from wood. The gift shop makes a $10 profit per unit sold during the season, but it takes a $5 loss per unit after the season is over. The following discrete probability distribution for the season s demand has been identified: Demand Demand Probability How many ornaments should the museum s buyer order? D 9 Finding for One-Period Decisions SOLUTION Each demand level is a candidate for best order quantity, so the payoff table should have five rows. For the first row, where = 10, demand is at least as great as the purchase quantity. Thus, all five payoffs in this row are Payoff = p = ($10)(10) = $100 This formula can be used in other rows but only for those quantity demand combinations where all units are sold during the season. These combinations lie in the upper-right portion of the payoff table, where D. For example, the payoff when = 40 and D = 50 is Payoff = p = ($10)(40) = $400 D 30 15

16 Finding for One-Period Decisions The payoffs in the lower-left portion of the table represent quantity demand combinations where some units must be disposed of after the season ( > D). For this case, the payoff must tbe calculated l with iththe second dformula. For example, when = 40 and D = 30, Payoff = pd l( D) = ($10)(30) ($5)(40 30) = $50 Using OM Explorer, we obtain the payoff table in Figure D.5 Now we calculate the expected payoff for each by multiplying the payoff for each demand quantity by the probability of that demand and then adding the results. For example, for = 30, Payoff = 0.($0) + 0.3($150) + 0.3($300) + 0.1($300) + 0.1($300) = $195 D 31 Finding for One-Period Decisions Figure D.5 OM Explorer Solver for One-Period Inventory Decisions Showing the Payoff Table D 3 16

17 Finding for One-Period Decisions Using OM Explorer, Figure D.6 shows the expected payoffs Figure D.6 OM Explorer Solver Showing the Expected Payoffs D 33 Application D.3 For one item, p = $10 and l = $5. The probability distribution for the season s demand is: Demand Demand (D) Probability Complete the following payoff matrix, as well as the column on the right showing expected payoff. (Students complete highlighted cells) What is the best choice for? D 34 17

18 Application D.3 D Expected Payoff 10 $100 $100 $100 $100 $100 $ D 35 Application D.3 D Expected Payoff 10 $100 $100 $100 $100 $100 $ Payoff if = 30 and D = 0: pd l( D) = 10(0) 5(30 0) = $150 Payoff if = 30 and D = 40: pd = 10(30) = $300 Expected payoff if = 30: = 30 has the highest payoff at $ (0.) + 150(0.3) + 300( ) = $195 D 36 18

19 Solved Problem 1 Peachy Keen, Inc., makes mohair sweaters, blouses with Peter Pan collars, pedal pushers, poodle skirts, and other popular clothing styles of the 1950s. The average demand for mohair sweaters is 100 per week. Peachy s production facility has the capacity to sew 400 sweaters per week. Setup cost is $351. The value of finished goods inventory is $40 per sweater. The annual per-unit inventory holding cost is 0 percent of the item s value. a. What is the economic production lot size (ELS)? b. What is the average time between orders (TBO)? c. What is the total of the annual holding cost and setup cost? D 37 Solved Problem 1 SOLUTION a. The production lot size that minimizes total cost is DS p ELS H p d 1005$ $ , sweaters 3 b. The average time between orders is ELS 780 TBO ELS 0.15 year D 5, 00 Converting to weeks, we get TBO ELS 0.15 year5 weeks/year 7.8 weeks D 38 19

20 Solved Problem 1 c. The minimum total of setup and holding costs is p d C H p D S , $ 40 $ 351 $,340/year $,340/year $4,680/year D 39 Solved Problem A hospital buys disposable surgical packages from Pfisher, Inc. Pfisher s price schedule is $50.5 per package on orders of 1 to 199 packages and $49.00 per package on orders of 00 or more packages. Ordering cost is $64 per order, and annual holding cost is 0 percent of the per unit purchase price. Annual demand is 490 packages. What is the best purchase quantity? SOLUTION We first calculate the EO at the lowest price: EO 00 DS 490 $ , packages H 0. 0 $ D 40 0

21 Solved Problem This solution is infeasible because, according to the price schedule, we cannot purchase 80 packages at a price of $49.00 each. Therefore, we calculate the EO at the next lowest price ($50.5): DS 490$ H 0. 0$ EO 5 6, packages This EO is feasible, but $50.5 per package is not the lowest price. Hence, we have to determine whether total costs can be reduced by purchasing 00 units and thereby obtaining a quantity discount. D 41 Solved Problem C C C 79 D H S PD $ $ $ $396.98/year 00 $396.68/year $4,6.50 $5,416.44/year $ $ $ $980.00/year $156.80/year $4, $5,146.80/year Purchasing 00 units per order will save $69.64/year, compared to buying 79 units at a time. D 4 1

22 Solved Problem 3 Swell Productions is sponsoring an outdoor conclave for owners of collectible and classic Fords. The concession stand in the T-Bird area will sell clothing such as T-shirts and official Thunderbird d racing jerseys. Jerseys are purchased from Columbia Products for $40 each and are sold during the event for $75 each. If any jerseys are left over, they can be returned to Columbia for a refund of $30 each. Jersey sales depend on the weather, attendance, and other variables. The following table shows the probability of various sales quantities. How many jerseys should Swell Productions order from Columbia for this one-time event? Sales uantity Probability uantity Sales Probability D 43 Solved Problem 3 SOLUTION Table D.1 is the payoff table that describes this one-period inventory decision. The upper right portion of the table shows the payoffs when the demand, D, is greater than or equal to the order quantity,. The payoff is equal to the per-unit profit (the difference between price and cost) multiplied by the order quantity. For example, when the order quantity is 100 and the demand is 00, Payoff = (p c) = ($75 - $40)100 = $3,500 D 44

23 Solved Problem 3 TABLE D.1 PAYOFFS Demand, D Expected Payoff 100 $3,500 $3,500 $3,500 $3,500 $3,500 $3,500 $3, $,500 $7,000 $7,000 $7,000 $7,000 $7,000 $6, $1,500 $6,000 $10,500 $10,500 $10,500 $10,500 $9, $500 $5,000 $9,500 $14,000 $14,000 $14,000 $10, ($500) $4,000 $8,500 $13,000 $17,500 $17,500 $10, ($1,500) $3,000 $7,000 $1,000 $16,500 $1,000 $9,750 D 45 Solved Problem 3 The lower-left portion of the payoff table shows the payoffs when the order quantity exceeds the demand. Here the payoff is the profit from sales, pd, minus the loss associated with returning overstock, l( D), ) where l is the difference between the cost and the amount refunded for each jersey returned and D is the number of jerseys returned. For example, when the order quantity is 500 and the demand is 00, Payoff = pd l( D) = ($75 - $40)00 ($40 $30)(500 00) = $4,000 The highest expected payoff occurs when 400 jerseys are ordered: Expected payoff 400 = ($ ) + ($5, ) + ($9, ) + ($14, ) + ($14, ) + ($14, ) = $10,805 D 46 3

24 D 47 4