Numerical Reasoning Test 10 Solutions

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1 Numerical Reasoning Test 10 Solutions Question 1: Step 1 - Find each city's number of managers Manchester: = 340 Birmingham: = 115 Edinburgh: = 52 Leeds: = 261 London: = 204 Step 2 - Find the average number per store 340 / 4 = / 5 = / 2 = / 3 = / 4 = 51 Thus the correct answer is (B), Birmingham Question 2: Step 1 - calculate the reduced numbers of units shipped from each location Birmingham: 3,500 x.93 = 3,255 Edinburgh: 5,300 x.95 = 5,035 Leeds: 6,600 x.88 = 5,808 Step 2 - calculate the reduced numbers of units warehoused from each location Birmingham: 5,200-3,255 = 1,945 Edinburgh: 8,800-5,035 = 3,765 Leeds: 8,700-5,808 = 2,892 Step 3 - Find London and Manchester's warehoused numbers of units London: 9,200-6,100 = 3,100 Manchester: 8,400-6,800 = 1,600 Step 4 - sum the numbers of units warehoused from each location 3, , , , ,892 = 13,302 Thus the correct answer is (C), 13,302

2 Question 3: Step 1 calculate the Manchester job cuts (2, ) x 8 / 100 = 221 Step 2 calculate the London job cuts (1, ) x 10 / 100 = 209 Step 3 calculate the total = 430 Thus the correct answer is (D), 430 Question 4: Step 1 Calculate sales total 9,200 x 5.5 = 50,600 Step 2 Calculate the previous sales At reduced price: 820 x 3.75 = 3,075 At sales price: 860 x 5.5 = 4,730 Step 3 Calculate the difference in sales that represents the additional sales made 50,600-4,730 3,075 = 42,795 Thus the correct answer is (E), 42,795 Question 5: Step 1 - for the C-696 find the difference between the cost to buy and to hire (81.86 x 36) - 2, = Step 2 - for the PX-250 find the difference between the cost to buy and to hire (58.43 x 48) - 1, = 1, Step 3 - total the two figures ,305.15= $1, = $1,800 to the nearest $100 Thus the correct answer is (A), $1,800

3 Question 6: Step 1 - find the total cost over 60-months for each of the office colour photocopiers shown as answer options AB-50: x 60 = 4,053 O-990: x 60 = 5,341 4-TES: x 60 = 6, Step 2 - find the total cost over 48-months for each office colour photocopier AB-50: x 48 = 3, TES: x 48 = 6, Step 3 - review to find the second most expensive Thus the correct answer is (E), 4-TES (49-month plan) Question 7: Remove the small poster cost from the budget 240 / 20 x $20 = $240 $3,350 - $240 = $3,110 There are many different combinations of the two price plans for business cards with which this $3,110 can be spent To maximise the number of business cards, the highest possible number of "1000 business cards for $45" must be adopted - so that any money left over is used to purchase business cards at the "50 for $6 rate" $3,110 / $45 = x 1000 = 69,000 business cards Budget remaining after 69 packs of cards: 3110 (69 x 45) = = $5 How many packs of 50 business cards can be bought with the remaining $5: one pack costs 6, so 0. Thus the correct answer is (C), 69,000

4 Question 8: Step 1 - Review the monthly costs and in your head estimate which could be in the In the region of 3-3,500, are likely to be the following: XP-550; AD-200; PX-250; XP- 550; and the P Step 2 - Calculate the total cost for these select few plans XP-550 (48 months): 2, P-4000 (48 months):3, AD-200 (60 months): 3,303 PX-250 (60 months): 3,297 XP-550 (60 months): 3, P-4000 (60 months): 3,366 Thus the correct answer is (B), AD-200 (60-months) Question 9: Step 1 - Calculate the production costs for each year Multiply Number of bikes sold by Average production cost 2012 = 64,561, = 56,223, = 53,759, = 54,055, = 49,966,400 = 50 million (to the nearest 1,000) Step 2 - Review to establish the year in question Year 2008 Step 3 - Find the Total bikes sales figure for that year Multiply Number of bikes sold by Average sales price = 13,360 x 6,430 = 85,904,800 = 85,900,000 (to the nearest 100,000) Thus the correct answer is (B), 85,900,000

5 Question 10: Step 1 - Find the Total cost for 2009 Production cost + Other costs = 4, ,746 = 5,852 Step 2 - Convert this figure to a % of sales price 5,852 / 7,160 = 81.7% Step 3 - Put this % into an equation (containing 2011 data) where Z = answer (4, ) / = Z Z = $5, (to 2 decimal places) Step 4, the percentage difference between the new 2011 price and old 2011 price: ( ) / 6040 x 100 = 6.53% to 2 d.p. Thus the correct answer is (E), 6.53% Question 11: Step 1 - Calculate the % change between each of the 5 years shown 2011/12 = 18.1% 2010/11 = - 8.5% 2009/10 = 13.1% 2008/09 = -1.5% Step 2 - Calculate the % change between each of the possible 2-years spans = 8.1% = 3.5% = 11.5% Step 3 - Review to find the answer (ignoring whether there was an increase or decrease in the number of bikes sold) Thus the correct answer is (E), None of the above Question 12: Step 1 - Calculate the Total bikes sales figure for each year Multiply Number of bikes sold by Average sales price 2012 = 96,583, = 82,325, = 86,718, = 94,261, = 85,904,800 Step 2 - Subtract Step 1's figures from the annual sales figures given (motorbikes and accessories) 101,300,000-96,583,900 = 4,716, ,200,000-82,325,200 = 23,874, ,500,000-86,718,000 = 17,782, ,100,000-94,261,400 = 11,838,600

6 103,800,000-85,904,800 = 17,895,200 Step 3 - Review Step 2 totals to establish which year is higher than 20 million Thus the correct answer is (D), 2011 Question 13: Step 1 - Calculate the total payment plan cost for each car Flume: = 329 x 36 (months) = 11,844 Rouser: = 299 x 36 = 10,764 Lior: = 185 x 60 = 11,100 Itro: = 230 x 48 = 11,040 Gaz: = 275 x 36 = 9,900 Step 2 - Find the difference in cost for each car Flume: 11,844-9,999 = 1,845 Rouser: 10,764-8,899 = 1,865 Lior: 11,100-9,499 = 1,601 Itro: 11,040-9,250 = 1,790 Gaz: 9,900-8,250 = 1,650 Step 3 - Convert to %'s of one-off cost Flume: 1,845 / 9,999 x 100% = 18.5% Rouser: 1,865 / 8,899 x 100% = 21.0% Lior: 1,601 / 9,499 x 100% = 16.9% Itro: 1,790 / 9,250 x 100% = 19.4% Gaz: 1,650 / 8,250 x 100% = 20.0% Step 4 - Review to find the car with the highest % saving on the cost price Thus the correct answer is (B), Rouser Question 14: Step 1 - Find how much petrol can be purchased over the two week holiday 35 x 14 (days) = 490 Step 2 - Convert this figure to Euros 490 x 1.25 = Euros Step 3 - Find how much petrol can be purchased / 1.9 = litres x 0.22 = 70.9 gallons Step 4 - Find how far a Lior will travel using that much petrol 70.9 x 45 = 3,191 miles Thus the correct answer is (B), 3,191 miles

7 Question 15: Step 1 - Calculate for each car the time taken to go from 60-90mph Flume: 7.8 x.6 = 4.68 Rouser: 10.1 x.6 = 6.06 Lior: 8.9 x.6 = 5.34 Itro: 9.4 x.6 = 5.64 Gaz: 10.5 x.6 = 6.3 Step 2 - Add this time to the 0-60mph time for each car Flume: 4.68 = 12.5 secs Rouser: 6.06 = 16.2 secs Lior: 5.34 = 14.2 secs Itro: 5.64 = 15.0 secs Gaz: 6.3 = 16.8 secs Thus the correct answer is (D), Itro Question 16: Step 1 - sum the CO2 emissions for the 3 cars = 279 Step 2 - put into a miles: km ratio 279 x 1.61 = g / per mile Step 3 - convert the emissions from g/km x 450 = 202,136 g = 202 kg Thus the correct answer is (C), 202 kg Question 17: Step 1 - calculate the average for each of the six rates Calls from landline (daytime) = 6.2 Calls from landline (evening) = 11.6 Calls using Telicity mobile (daytime) = 7.4 Calls using Telicity mobile (evening) = 13.4 Calls using different mobile (daytime) = 9 Calls using different mobile (evening) = 15 Step 2 - review to establish which are equal to 7.4p per minute Thus the correct answer is (E), Calls using Telicity mobile (daytime)

8 Question 18: Step 1 Update the costs Landline calls: 15p x 1.1 = 16.5p Different mobile: 20p x 1.1 = 22p Telecity mobile: 18p x 1.1 = 19.8p Step 2 - Calculate the daily costs Landline calls: 16.5p x 4 = 66p Different mobile: 22p x 5 = 110p Telecity mobile: 19.8p x 3 = 59.4p Step 3 Sum the above to get the total daily cost 66p + 110p p = 235.4p Step 4 - calculate the weekly cost x 7 = = 16 (to the nearest ) Thus the correct answer is (B), 16 Question 19: Step 1 - total the 3 fees = Step 2 - Percentage difference: / 34 x 100 = 167% (to nearest %) Thus the correct answer is (C), 167% Question 20: Step 1 - total the 3 fees = Step 2 - Calculate the cost exclusive of VAT 56.67/1.2 = Thus the correct answer is (A), 47.23

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