Selected Worked Homework Problems. Step 1: The GCF must be taken out first (if there is one) before factoring the hard trinomial.
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1 Section 7 4: Factoring Trinomials of the form Ax 2 + Bx + C with A >1 Selected Worked Homework Problems 1. 2x 2 + 5x + 3 Step 1: The GCF must be taken out first (if there is one) before factoring the hard trinomial. There is no GCF so factor 2x 2 + 5x + 3 Create an Easy Trinomial by moving the coefficient of the x 2 term to the end of the trinomial and multiplying the constant term by that coefficient Move the 2 to the right end of the trinomial and multiply it by the constant 3 to get 6 2x 2 + 5x x 2 + 5x + 6 Step 3: Factor the easy trinomial ( x + 2) ( x + 3 ) Step 4: In step 1 you multiplied the constant 1 by the coefficient of the x 2 term. 2 x Now divide BOTH of the constants that have been added or subtracted form the x term in the factors by that the coefficient. reduce each fraction that can be reduced (no mixed numbers) 2 x + 2 ( ) ( 2x + 3) ( x +1) You can check your answer by FOIL ing the factors ( 2x + 3) ( x +1) = 2x 2 + x + 4x + 3 = 2x 2 + 5x + 3 Math 100 Section 7 4 HW WKD 2016 Eitel
2 2. 3x 2 2x 5 Step 1. There is no GCF so factor 3x 2 2x 5 3x 2 2x 5 3 x 2 2x 15 Step 3: Factor the easy trinomial ( x 5 ) ( x + 3 ) Step 4: Divide each constant added or subtracted from x by 3 x and then reduce each fraction that can be reduced (no mixed numbers) x 5 3 ( x +1) Answer: ( 3x 5) ( x +1) You can check your answer by FOIL ing the factors ( 3x 5) ( 2x + 3) = 6x 2 + 9x 10x 15 = 6x 2 x 15 Math 100 Section 7 4 HW WKD 2016 Eitel
3 3. 6x 2 + 7x 3 Step 1. There is no GCF so factor 6x 2 + 7x 3 6x 2 + 7x 3 6 x 2 + 7x 18 Step 3: Factor the easy trinomial ( x 2 ) ( x + 9 ) Step 4: Divide each constant added or subtracted from x by 6 x 2 x and then reduce each fraction that can be reduced (no mixed numbers) x Answer: ( 3x 1) ( 2x + 3) You can check your answer by FOIL ing the factors ( 3x 1) ( 2x + 3) = 6x 2 + 7x 2x + 3 = 6x 2 + 7x + 3 Math 100 Section 7 4 HW WKD 2016 Eitel
4 4. 4x 2 5x 6 Step 1. There is no GCF so factor 4x 2 5x 6 4x 2 5x 6 4 x 2 5x 24 Step 3: Factor the easy trinomial ( x + 3 ) ( x 8 ) Step 4: Divide each constant added or subtracted from x by 4 4 x 8 4 and then reduce each fraction that can be reduced (no mixed numbers) 4 x 2 ( ) Answer: ( 4x + 3) ( x 2) You can check your answer by FOIL ing the factors ( 4x + 3) ( x 2) = 4x 2 + 3x 8x 6 = 4x 2 5x + 6 Math 100 Section 7 4 HW WKD 2016 Eitel
5 5. 8x 2 17x + 2 Step 1. There is no GCF so factor 8x 2 17x + 2 8x 2 17x x 2 17x +16 Step 3: Factor the easy trinomial ( x - 1) ( x 16 ) Step 4: Divide each constant added or subtracted from x by 8 x 1 8 x 16 8 and then reduce each fraction that can be reduced (no mixed numbers) x 1 8 x 2 ( ) Answer: ( 8x 1) ( x 2) You can check your answer by FOIL ing the factors ( 8x 1) ( x 2) = 16x 2 1x 16x + 2 = 8x 2 16x + 2 Math 100 Section 7 4 HW WKD 2016 Eitel
6 6. 3x 2 + 7x + 8 Step 1. There is no GCF so factor 3x 2 + 7x + 8 3x 2 + 7x x 2 + 7x + 24 Step 3: Factor the easy trinomial x 2 + 7x + 24 DOES NOT FACTOR so 3x 2 + 7x + 8 DOES NOT FACTOR 14. 9x 2 + 6x +1 Step 1. There is no GCF so factor 9x 2 + 6x +1 9x 2 + 6x +1 9 x 2 + 6x + 9 Step 3: Factor the easy trinomial ( x + 3) ( x + 3) Step 4: Divide each constant added or subtracted from x by and then reduce each fraction that can be reduced (no mixed numbers) x + 1 x Answer: ( 3x +1) ( 3x +1) Math 100 Section 7 4 HW WKD 2016 Eitel
7 15. 5x 2 7x +1 Step 1. There is no GCF so factor 5x 2 7x +1 5x 2 7x +1 5 x 2 7x + 5 Step 3: Factor the easy trinomial x 2 7x + 5 DOES NOT FACTOR so 5x 2 7x +1 DOES NOT FACTOR x 2 + 5x 3 Step 1. There is no GCF so factor 12x 2 + 5x 3 12x 2 + 5x 3 12 x 2 + 5x 36 Step 3: Factor the easy trinomial ( x 4) ( x + 9) Step 4: Divide each constant added or subtracted from x by 12 x 4 12 x and then reduce each fraction that can be reduced (no mixed numbers) x Answer: ( 3x 1) ( 4x + 3) Math 100 Section 7 4 HW WKD 2016 Eitel
8 Factoring Completely: Step 1: Factor out the GCF Factor the expression inside the parenthesis x 2 +10x + 6 Step 1. The GCF is 2. Factor out a 2 4x 2 +10x + 6= 2 ( 2x 2 + 5x + 3) now factor 2x 2 + 5x + 3 2x 2 + 5x x 2 + 5x + 6 Step 3: Factor the easy trinomial 2 ( x +3 ) ( x + 2 ) Step 4: Divide each constant added or subtracted from x by x and then reduce each fraction that can be reduced (no mixed numbers) 2 x x +1 ( ) Answer: 2 ( 2x + 3) ( x +1) Math 100 Section 7 4 HW WKD 2016 Eitel
9 Factoring Completely: Step 1: Factor out the GCF Factor the expression inside the parenthesis x 2 +10x 4 Step 1. The GCF is 2. Factor out a 2 6x 2 +10x 4 = 2 ( 3x 2 + 5x 2) now factor 3x 2 + 5x 2 3x 2 + 5x 2 3 x 2 + 5x 6 Step 3: Factor the easy trinomial 2 ( x 1 ) ( x + 6 ) Step 4: Divide each constant added or subtracted from x by 3 2 x 1 3 x and then reduce each fraction that can be reduced (no mixed numbers) 2 x 1 3 x + 2 ( ) Answer: 2 ( 3x 1) ( x + 2) Math 100 Section 7 4 HW WKD 2016 Eitel
10 Factor Completely x 2 30x + 9 Step 1. The GCF is 3. Factor out a 3 6x 2 30x + 9 = 3( 2x 2 10x + 3) now factor 2x 2 10x + 3 2x 2 10x x 2 10x + 6 Step 3: Factor the easy trinomial x 2 10x + 6 DOES NOT FACTOR so Answer: 3( 2x 2 10x + 3) Note: DNF is not correct. You factored out a 3 so the original polynomial DID factor ( ) does not factor any further, but 3 2x 2 10x + 3 Math 100 Section 7 4 HW WKD 2016 Eitel
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