BACHELOR'S DEGREE PROGRAMME

Transcription

1 No. of Printed Pages : 6 ECO-007 BACHELOR'S DEGREE PROGRAMME Term-End Examination June, ELECTIVE COURSE : COMMERCE ECO-007 : ELEMENTS OF STATISTICS Time : 2 hours Maximum Marks : 50 Weightage : 70% Note : There are three sections and all are compulsory. SECTION - A 1. Fill in the blanks with appropriate Ovoids given in the brackets : 5x1=5 (a) The census method of investigation is not possible when the universe is in size. (finite/ infinite). (b) The value of can be located with the help of a histogram. (mean/mode) (e) It is better to calculate mean deviation about. (mean/median) In a positively skewed distribution median is greater than. (mean/mode) The typing errors committed by a typist on a page is an example of variable. (discrete/ continuous) ECO P.T.O.

2 2. State whether the statements given below are true or false. 5x1=5 (a) (b) (e) In systematic sampling, a sample composed of every n th item is selected. Negative values cannot be represented in a histogram. The sum of deviations' of individual values from their arithmetic mean is always equal to zero. Mean Deviation cannot be negative. Co-efficient of variation is always presented in percentage. SECTION - B Attempt any two of the following : 3. (a) Construct a histogram for the following data : 10+5=15 Class interval : Frequency (b) Write a note on Pie diagram. 4. (a) The mean of a set of 75 observations was calculated as It was discovered later that an item of value 96 was wrongly taken as 26. Determine the correct mean. 6+9=15 (b) Calculate the value of mode from the following data : Class Interval : Frequency : ECO-007 2

3 5. (a) Using the following data, calculate mean deviation about median. 10+5=15 Marks : Frequency : (b) Calculate co-efficient of Variation from the following data. Mean = 85, Variance =16 6. (a) Write a note on historigram. 6+9=15 (b) Explain the method of Karl Pearson's coefficient of skewness. SECTION - C 7. Differentiate between any two of the following : (a) (b) One Dimensional Diagram and Two Dimensional Diagram. 5+5=10 Primary data and Secondary data. Discrete and Continuous Variables. Absolute and Relative Variations. ECO-007 3

4 5. (a) gci 7:12tA 3TRITTITT 4 Trrfizrwr Trrai ra-r-m-c nuilt fit : 10+5= , (b) NTTut rc kul TrifT (co-efficient of Variation) chl W12i=85, qt.rill (Variance) =16 6. (a) ow rich fq7 (Historigram) tr -crwteirt ffftf7 I (b) chic4 ii-lq-1-1**errzt7u tfit Wlf-A7 I 6+9=15 'WS ' r4T =10 (a) 7W-rcii-icfici 3-11"(131 7gT rgicv-icficf atitta (b) attwt 7q1 fgetzm 37.** 7 ifz7 (Discrete) 7 2 TT 3TZgift7 (Continuous) tiffkt 72.1T 1:114V tql7 (Variations) ECO-007 6

5 t--ii rich 3 1-1I NT chi t-ia I h TRkt.ii 1.4% , : 41 f-ish+i : (41 ui \re-i T:2 rtrr - 37filTh 'W :50 Tff chi : 70% : ff-77 C9' 0.5 7Q1T 7:1113 alftaref g I (gu8 - at 1. TR T:l.cf gr1 ftwr Tqt 5x1=5 ah~ l I (a) TT9. t 4 4 1u1-11 RAT (census method) 1-1-q )c11 z14 T 31TWR t I (Iffffrid/31 1:1fiflid) (b) TT (value) r-ci, 1 (histogram) ch t 11(-11 gild f*-74t kichclf t I ( 11-1t71/ 1.1#11 ) TTII74 chl 1 1 1J1-11 a,( FqT3T T t I ocrib7t/trrftzr*0 qa-f-trt. Faqi-i fa--ttai -11{fzrwr 31-N -T ( -Frruip) (e) ZTOIR gri f-*7# -cr- -ER 'I ZTT t (variable) (51.-ft7/31-dftU) ECO P.T.O.

6 2. TM- We "r". tgc chl-f-tet +irici I 5x1=5 (a) 1.> -wqr-t-p-47 Mrdlt A-T nth.7:1 (=Ha -5rf-d--o w.1-1 \Aim t1 (b) 1 ch airqu rcii (histogram) 14 TAT 311--d-r9-Fe Whcil 374 ( CR -1:1R-Tfti ce-irchvicf 1=74 -*Ri -cm-ii #71-r qk4 i I ITTar t-ichii I (e) t7177 1juTEW (Co-efficient of Variation) #711 9f717 (percentage) * r -4?1 "arqff f*-tit \-1-int I 'urn -w rii-ircifigi itraq I 3. (a) i1+-irciftgo * 3iINT7 TIT 7W f77 (histogram) : 10+5=15 (b) cy : airlt : tgf (Pie diagram) TR "crq re.viurl fftri i 4. (a) 75 tftt * * tii-iicritt7 (mean) +1c-ti 80.4 LiRchrrict 717T I 77 TM Ti c (b). 771 fw 4m4) A. 96 itc-ti * -4,7 TT 1,7f 26 t t-14-liot *f-77 I 6+9=15 ~ir i 7111*r-77 : 71#0* 31117tRii-P:11Z* (mode) wirt-1-t f-9 : ECO P.T.O.