Level 3 Certificate MATHEMATICAL STUDIES 1350/2B

Transcription

1 SPECIMEN MATERIAL Level 3 Certificate MATHEMATICAL STUDIES 1350/2B Paper 2B Critical path and risk analysis Mark scheme Specimen Version 1.1

2 Mark schemes are prepared by the Lead Assessment Writer and considered, together with the relevant questions, by a panel of subject teachers. This mark scheme includes any amendments made at the standardisation events which all associates participate in and is the scheme which was used by them in this examination. The standardisation process ensures that the mark scheme covers the students responses to questions and that every associate understands and applies it in the same crect way. As preparation f standardisation each associate analyses a number of students scripts. Alternative answers not already covered by the mark scheme are discussed and legislated f. If, after the standardisation process, associates encounter unusual answers which have not been raised they are required to refer these to the Lead Assessment Writer. It must be stressed that a mark scheme is a wking document, in many cases further developed and expanded on the basis of students reactions to a particular paper. Assumptions about future mark schemes on the basis of one year s document should be avoided; whilst the guiding principles of assessment remain constant, details will change, depending on the content of a particular examination paper. Further copies of this mark scheme are available from aqa.g.uk Page 2 Version 1.1

3 MARK SCHEME LEVEL 3 MATHEMATICAL STUDIES SPECIMEN PAPER - PAPER 2B Principal Examiners have prepared these mark schemes f specimen papers. These mark schemes have not, therefe, been through the nmal process of standardising that would take place f live papers. Further copies of this Mark Scheme are available from aqa.g.uk Glossary f Mark Schemes Examinations are marked in such a way as to award positive achievement wherever possible. Thus, f mathematics papers, marks are awarded under various categies. If a student uses a method which is not explicitly covered by the mark scheme the same principles of marking should be applied. Credit should be given to any valid methods. Examiners should seek advice from their seni examiner if in any doubt. M dm A B E ft CAO CSO AWFW AWRT ACF AG SC OE mark is f method mark is dependent on one me M marks and is f method mark is dependent on M m marks and is f accuracy mark is independent of M m marks and is f method and accuracy mark is f explanation follow through from previous increct result crect answer only crect solution only anything which falls within anything which rounds to any crect fm answer given special case equivalent A2,1 2 1 ( 0) accuracy marks PI SCA c sf dp possibly implied substantially crect approach candidate significant figure(s) decimal place(s) Version 1.1 Page 3 of 14

4 Q Answer Mark Comments 1 the numbers in column D can be automatically calculated by using a sum fmula to add those in columns B and C cell D3 should be 23 cell D3 has not been added up crectly cell B3 Cell C3 may have the wrong value as they don t add up to 33 comments on sampling. eg sample size too small he has not asked the whole class no time period is given so an average per day cannot be calculated comments on lack of average, eg.no averages mentioned: texts per person per day similar is expected totals cells needed/cell with fmula to calculate average collection of texts received is irrelevant B3 each crect statement Page 4 Version 1.1

5 MARK SCHEME LEVEL 3 MATHEMATICAL STUDIES SPECIMEN PAPER - PAPER 2B Q Answer Mark Comments Alt = (not ) This is the amount the bank will lend him. Pete should divide by 0.9 (instead of multiplying by 0.9) This is to find the maximum house price he can affd. There is no purpose to the multiplication done. ( ) This is the maximum price he can affd f a house. Alt ( ) This is the maximum price he can affd f a house. 3(a) says that the complaint was justified and gives any two of the following reasons column headings needed the last column should be stated to be percentages the last but one column should be stated to be votes received all candidates should be listed the total electate should be stated the percentage turnout is omitted E2 equivalent E1 says that the complaint was justified and gives one crect reason (igne any increct reasons given) gives two crect reasons but does not say that the complaint was justified Version 1.1 Page 5 of 14

6 Q Answer Mark Comments 3 (b) calculates 2010 electate: [71 740, 71750] uses their 2010 figure to make a sensible estimate of the 2014 figure and makes a valid conclusion based on 50% of their electate says that UKIP did make the biggest numerical gain and gives evidence oe eg assumes the electate remains stable and compares half of their electate assumes an increase in electate and compares half of their increased electate SC1 says that as we are not told the number of registered voters in 2014 we cannot say if half did not vote relevant figures are: Conservative Labour 4596 Liberal 9242 UKIP condone UKIP were the only ones of the four parties from 2010 to increase their vote there is no need f a comment about the parties who did not take part in 2010, but accept any crect comment eg the other parties cannot have increased their vote beyond the 1891 of the independent candidate says that UKIP did make the biggest percentage gain and gives evidence E1 relevant figures are: Conservative 8.9(%) Labour 4.6(%) Liberal 17.4(%) UKIP (%) condone UKIP were the only ones of the four parties from 2010 to increase their vote there is no need f a comment about the parties who did not take part in 2010, but accept any crect comment eg the other parties cannot have increased their vote beyond the 4.9% of the independent candidate Page 6 Version 1.1

7 MARK SCHEME LEVEL 3 MATHEMATICAL STUDIES SPECIMEN PAPER - PAPER 2B Q Answer Mark Comments 3(c) Jenrick (Conservative) Conservatives did gain a majity, however me people voted against them (47.65) than f them (45%) full well communicated comment putting both sides E2 E1 f partial explanation eg Jenrick was crect as Conservatives gained me votes than any other party Jenrick is wrong as me people voted against the government (46.7%) than f the government (45%) the government is a coalition so including the Liberal Democrat percentage gives the government an even bigger majity (47.6%) Helmer (UKIP) any comparison of 3.8 and 25.9 no credit f result in general election approx fact of 5 as not a justification so he is right is approx 7 so he is wrong = 22.8 so it s me than a fact of 6 any comparison of and = 8076 and yes / they me than halved the majity Payne (Labour) various sensible numerical arguments are possible, f example reference to the 45.0 % being less than half E1 can conclude they agree disagree with Helmer with crect reasoning Version 1.1 Page 7 of 14

8 only a quarter of the electate voted against the Conservative candidate clearly communicated answers with links to each candidate s statement and numerical justifications Page 8 Version 1.1

9 MARK SCHEME LEVEL 3 MATHEMATICAL STUDIES SPECIMEN PAPER - PAPER 2B Q Answer Mark Comments 4(a) SCA at least 10 activities 2 me floats seen A2, 1, 0 1 each independent err minimum 30 condone 38, if valid reason given maximum 45 condone 30, if valid reason given and greater than equal to minimum above 4(b) D: no effect and N: delay by 2 hours complete 47 hours Version 1.1 Page 9

10 Q Answer Mark Comments Alt probability of winning 20 their number of races won their = 4000 total winnings total entry fee 4000 their 1000 ( )3000 Alt number of races finished their number of races won their 8 (500 50) 3600 amount won in races won (20 their 8) amount lost in races lost 3600 their 600 ( )3000 Alt probability of winning and 50 net winnings and net losses = = 0.4 and = = = 150 ( ) 20 ( ) probability of losing expected winning per race ( )3000 Page 10 Version 1.1

11 MARK SCHEME LEVEL 3 MATHEMATICAL STUDIES SPECIMEN PAPER - PAPER 2B Q Answer Mark Comments Alt W 0.8 F 0.5 L 0.2 F P(win) = = 0.4 and P(lose) = = 0.6 P(win) = = 0.4 and P(lose) = = (500 50) 3600 amount won in races won amount lost in races lost 3600 their 600 ( )3000 Version 1.1 Page 11

12 Q Answer Mark Comments 6(a) see diagram below also accept methods based on activities on arcs convention netwk, at least 9 activities and some arcs up to 2 independent errs all crect fward pass, crect at D all crect back pass, crect at H, I, J, ft all crect A B C D E F G H I J K (b) (Critical) A C D G H I K Alt 1 6(c) counts their 18 weeks (126 days) from July 1st November 3 November 4 ft ft their number of weeks in (a) no, with November 3 November 4 explanation that they will be 2 3 days late E1ft ft their number of weeks in (a) Alt 2 6(c) counts their 18 weeks (126 days) from Nov 1st June 28 June 29 ft ft their number of weeks in (a) no, with June 28 June 29 explanation that they will be 2 3 days late E1ft ft their number of weeks in (a) Page 12 Version 1.1

13 MARK SCHEME LEVEL 3 MATHEMATICAL STUDIES SPECIMEN PAPER - PAPER 2B Q Answer Mark Comments 7(a) 4 and 14 identified eg and (b) = = (a) = 0.37 ( ) + ( ) + ( ) = 0.37 the delays in the two activities are independent = (b) recommend preventing a delay on y only E1 recommend both y costs less than others E1 both not much me expensive and may be wth the investment to protect contract s reputation y = 10,000 if three values crect none = x = A2 A2 f all crect and seen x and y = Version 1.1 Page 13

14 Copyright 2014 AQA and its licenss. All rights reserved. AQA retains the copyright on all its publications. However, registered schools/colleges f AQA are permitted to copy material from this booklet f their own internal use, with the following imptant exception: AQA cannot give permission to schools/colleges to photocopy any material that is acknowledged to a third party even f internal use within the centre. SP/01/14 Page 14 Version 1.1