Web Extension: The Binomial Approach

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19878_06W_p001-009.qxd 3/10/06 9:53 AM Page 1 C H A P T E R 6 Web Extension: The Binomial Approach The example in the chapter illustrated the binomial approach. This extension explains the approach in more detail and illustrates its application when the year is divided into more than one period. The stock of Western Cellular sells for P0 $40 per share. Options exist that permit the holder to buy one share of Western at an exercise price of $35. These options will expire at the end of one year. The steps to the binomial approach are shown below. IMAGE: GETTY IMAGES, INC., PHOTODISC COLLECTION See the IFM9 Ch06 Tool Kit.xls for all the calculations. STEP 1. Define the possible ending prices of the stock. Suppose our analysis of Western s stock indicates that the standard deviation ( ) of its expected annual stock return is 22.314 percent. The binomial approach assumes that Western s stock will be selling at one of two prices at the end of the period. In particular, it assumes the initial stock price will go up by a multiplicative factor (u) or go down by a multiplicative factor (d). In other words, the ending stock price for an upward movement, Pu, is Pu u(p0), and the ending stock price for a downward movement, Pd, is Pd d(p0). The trick is to choose u and d so that the resulting standard deviation of stock returns is equal to the desired annual standard deviation of 22.314 percent. The derivation is beyond the scope of a financial management textbook, but the appropriate equations are u e 2T/n 6E-1 and 6E-1

19878_06W_p001-009.qxd 3/10/06 9:53 AM Page 2 d 1 u 6E-2 where T is the time in years until the option expires and n is the number of steps per year. Western s option has one year until it expires, and we are initially assuming there is only one step during the year. Therefore, u and d are u e 2T / n e 0.2231421 /1 1.25 d 1 u 1 0.80 1.25 Based on these values of u and d, the ending stock prices are P u 1.25($40) $50 and P d 0.80($40) $32. Notice that if Western were a riskier stock, then its standard deviation would be higher than 22.314 percent. This would cause u to be higher than 1.25 and d to be lower than 0.80, resulting in a wider range of possible ending stock prices. Figure 6E-1 illustrates the stock s possible price paths when 22.314%; the other information in the figure is explained below. STEP 2. Find the range of values at expiration. When the option expires at the end of the year, Western s stock will sell for either $50 or $32, a range of $50 $32 $18. As shown in Figure 6-2 in the chapter, the option will pay $15 if the stock is $50, because this is above the exercise price of $35: $50 $35 $15. The option will pay nothing if the stock price is $32, because this is below the exercise price. The range of option payoffs is $15 $0 $15. The hedger s portfolio consists of the stock and the obligation to satisfy the option holder, so the value of the portfolio in one year is the stock price minus the option payoff. STEP 3. Buy exactly enough stock to equalize the range of payoffs for the stock and the option. Figure 6-2 shows that the ranges of payoffs for the stock and the option are $18 and $15. To construct the riskless portfolio, we need to equalize these ranges so that the profits from the stock exactly offset the losses in satisfying the option holder. We do so by buying $15/$18 0.8333 share and selling one option (or 8,333 shares and 10,000 options). Here is why equalizing ranges gives the correct number of shares of stock. Let C u be the call option payoff if the stock goes up, C d the call option payoff if the stock goes down, and N the number of shares of stock. We want the portfolio value to be the same whether the stock is high or low. The portfolio value for a high stock price is N(P u ) C u, and the value for a low stock price is N(P d ) C d. Setting these equal and solving for N yields N C u C d P u P d which is the same as equalizing the ranges. 6E-2 Chapter 6 Web Extension: The Binomial Approach

19878_06W_p001-009.qxd 3/10/06 9:53 AM Page 3 Figure 6E-1 Binomial Approach $50.00 Max [$50 $35, 0] $15.00 (Stock Option) $50 $15 $35.00 $40 $32.00 Max [$32 $35, 0] $ 0.00 (Stock Option) $32 $ 0 $32.00 Range of Outcomes: $18.00 $15.00 $ 3.00 With 0.8333 share of stock, the current value of the stock in the portfolio is $40(0.8333) $33.33. The value of the portfolio s stock at the end of the year will be either $50(0.8333) $41.67 or $32(0.8333) $26.67. As shown in Figure 6E-2, the range of the stock s ending value is now $41.67 $26.67 $15. STEP 4. Create a riskless hedged investment. We created a riskless portfolio by buying 0.8333 share of the stock and selling one call option, as shown in Figure 6E-2. The stock in the portfolio will have a value of either $41.67 or $26.67, depending on the ending price of Western s stock. The call option that was sold will have no effect on the value of the portfolio if Western s price falls to $32, because it will not be exercised it will expire worthless. However, if the stock price ends at $50, the holder of the option will exercise it, paying the $35 exercise price for stock that would cost $50 on the open market. The option holder s profit is the option writer s loss, so the option will cost the hedger $15. Now note that the value of the portfolio is $26.67 regardless of whether Western s stock goes up or down, so the portfolio is riskless. A hedge has been created that protects against both increases and decreases in the price of the stock. STEP 5. Find the call option s price. To this point, we have not mentioned the price of the call option that was sold to create the riskless hedge. What is the fair, or equilibrium, price The value of the portfolio will be $26.67 at the end of the year, regardless of what happens to the price of the stock. This $26.67 is riskless, and so the portfolio should earn the riskfree rate, which is 8 percent. In the chapter, we used daily compounding; technically, we should use continuous compounding. The present value of the portfolio s ending value is PV $26.67e r RFt $26.67e 0.08(1) $24.62 This means that the current value of the portfolio must be $24.62 to ensure that the portfolio earns the risk-free rate of return. The current value of the portfolio is equal to the value of the stock minus the value of Chapter 6 Web Extension: The Binomial Approach 6E-3

19878_06W_p001-009.qxd 3/10/06 9:53 AM Page 4 Figure 6E-2 The Hedge Portfolio b $41.67 Max [$50 $35, 0] $15.00 (Stock Option) $41.67 $15 $26.67 a $33.33 c $26.67 Max [$32 $35, 0] $ 0.00 (Stock Option) $26.67 $ 0 $26.67 Range of Outcomes: $15.00 $15.00 $ 0.00 Notes: a The portfolio contains 0.8333 share of stock, with a stock price of $40, so its value is 0.8333($40) $33.33. b The ending stock price is $50, so the value is 0.8333($50) $41.67. c The ending stock price is $32, so the value is 0.8333($32) $26.67. the obligation to cover the call option. At the time the call option is sold, the obligation s value is exactly equal to the price of the option. Because Western s stock is currently selling for $40, and because the portfolio contains 0.8333 share, the value of the stock in the portfolio is 0.8333($40) $33.33. What remains is the price of the option: PV of portfolio value of stock in portfolio option price option price value of stock in portfolio PV of portfolio $33.33 $24.62 $8.71 If this option sold at a price higher than $8.71, other investors could create riskless portfolios as described above and earn more than the riskless rate. Investors (especially the large investment banking firms) would create such portfolios and sell options until their price fell to $8.71, at which point the market would be in equilibrium. Conversely, if the options sold for less than $8.71, investors would create an opposite portfolio by buying a call option and selling short the stock. The resulting supply shortage would drive the price up to $8.71. Thus, investors (or arbitrageurs) would buy and sell in the market until the options were priced at their equilibrium level. Clearly, this example is unrealistic. Although you could duplicate the purchase of 0.8333 share by buying 8,333 shares and selling 10,000 options, the stock price assumptions are unrealistic; Western s stock price could be almost anything after one year, not just $50 or $32. However, if we allowed the stock to move up or down more often during the year, then a more realistic range of ending prices would result. In fact, if we allowed hundreds, or even thousands, of up and down stock price movements during the year, the resulting distribution of stock prices 6E-4 Chapter 6 Web Extension: The Binomial Approach

19878_06W_p001-009.qxd 3/10/06 9:53 AM Page 5 would approximate the distributions of actual stocks. To see how the binomial approach can accommodate more than one up or down movement in the year, suppose we allowed the stock to move up or down every six months. As before, we must choose u and d so that the resulting standard deviation of annual stock returns is equal to the desired standard deviation of 22.314 percent. Western s option still has one year until it expires, but we are now assuming there are two steps during the year. Therefore, the new values of u and d are u e 2T / n e 0.2231421 /2 1.1709 d 1 u 1 0.8540 1.1709 See IFM9 Ch06 Tool Kit.xls for all calculations. Based on these values of u and d, the ending stock price for two upward movements is 1.1709(1.1709)($40) $54.84. For two downward movements, the ending stock price is 0.8540(0.8540)($40) $29.17. If the stock goes up and then down, the ending price is 1.1709(0.8540)($40) $40. The range of outcomes is a little larger than in Figure 6E-1, but the standard deviation of stock returns is the same, because most of the time the stock is expected to end up in the middle, rather than on the top or bottom. Keeping the standard deviation the same as in Figure 6E-1 allows us to compare apples and apples, rather than apples and oranges. The pattern of stock prices shown in Figure 6E-3 is called a binomial lattice. If we focus only on the portion of the lattice shown inside the oval, it is very similar to the problem we just solved in Figure 6E-1, except it has slightly different stock prices. We can apply the same solution procedure to find the price of the option at the end of six months, given a six-month stock price of $46.84. Figure 6E-4 shows this part of the lattice, including the stock prices and option payoffs. The next step is to find the number of shares of stock needed to create the hedge portfolio for the upper right portion of the lattice: N C u C d $19.84 $5.00 P u P d $54.84 1 Figure 6E-3 The Binomial Lattice $40 $46.84 $34.16 $54.84 $29.17 Chapter 6 Web Extension: The Binomial Approach 6E-5

19878_06W_p001-009.qxd 3/10/06 9:53 AM Page 6 Figure 6E-4 Payoffs for the Upper Right Portion of the Binomial Lattice in Figure 6E-3 $54.84 Max [$54.84 $35, 0] = $19.84 $54.84 $19.84 = $35.00 $46.84 Max [ $35, 0] = $ 5.00 $5.00 = $35.00 Range of Outcomes: $14.84 $14.84 $ 0.00 With one share of stock and one option in the hedge portfolio, the payoffs of the portfolio are shown in Figure 6E-5. Notice that the hedge portfolio in Figure 6E-5 has a payoff of $35 no matter whether the stock goes up or down. Thus, the value of the portfolio should be the present value of the payoff discounted at the risk-free rate. Therefore, if the stock price in six months is $46.84, then the value of the portfolio in six months is Portfolio value $35e 0.08(0.5) $33.628 Because the portfolio is comprised of a long position of N shares of the stock and a short position in the option, the value of the option in six months (if the stock price in six months is $46.84) is Option at six months N(P) Portfolio value 1($46.84) $33.628 $13.21 Thus, the option will be worth $13.21 in six months if the stock price goes up to $46.84. The next step is to find the value of the option in six months if the stock price goes down to $34.16. We can do this by solving the binomial problem in the lower right corner of Figure 6E-3. Figure 6E-6 shows this part of the lattice, including the stock prices and option payoffs. The next step is to find the number of shares of stock needed to create the hedge portfolio for the lower right portion of the lattice: N C u C d P u P d $5.00 $0.00 0.462 $29.17 With 0.462 share of stock and one option in the hedge portfolio, the payoffs of the portfolio are shown in Figure 6E-7. Notice that the hedge portfolio in Figure 6E-7 has a payoff of $13.48 no matter whether the stock goes up or down. Thus, the value of the portfolio should be the present value of the payoff discounted at the risk-free rate. Therefore, if the stock price in six months is $34.16, then the value of the portfolio in six months is Portfolio value $13.48e 0.08(0.5) $12.951 6E-6 Chapter 6 Web Extension: The Binomial Approach

19878_06W_p001-009.qxd 3/10/06 9:53 AM Page 7 Figure 6E-5 The Hedge Portfolio for the Upper Right Portion of the Lattice in Figure 6E-3 b $54.84 Max [$54.84 $35, 0] = $19.84 $54.84 $19.84 = $35.00 a $46.84 c Max [ $35, 0] = $ 5.00 $5.00 = $35.00 Range of Outcomes: $14.84 $14.84 $ 0.00 Notes: a The portfolio contains one share of stock, with a stock price of $46.84, so its value is 1($46.84) $46.84. b The ending stock price is $54.84, so the value is 1($54.84) $54.84. c The ending stock price is $40, so the value is 1($40). Figure 6E-6 Payoffs for the Lower Right Portion of the Binomial Lattice in Figure 6E-3 Max [ $35, 0] = $5.00 $5.00 = $35.00 $34.16 $29.17 Max [$29.17 $35, 0] = $0.00 $29.17 $0.00 = $29.00 Range of Outcomes: $10.83 $5.00 $ 6.00 Because the portfolio is comprised of a long position of N shares of the stock and a short position in the option, the value of the option in six months (if the stock price in six months is $34.16) is Option at six months N(P) Portfolio value 0.462($34.16) $12.951 $2.83 Thus, the option will be worth $2.83 in six months if the stock price goes down to $34.16. Now that we know the value of the option in six months for either an upward or downward change in stock price, we can solve the first part of the lattice from Figure 6E-3, as shown in Figure 6E-8. Chapter 6 Web Extension: The Binomial Approach 6E-7

19878_06W_p001-009.qxd 3/10/06 9:53 AM Page 8 Figure 6E-7 The Hedge Portfolio for the Lower Right Portion of the Binomial Lattice in Figure 6E-3 b $18.48 Max [ $35, 0] = $5.00 $18.48 $5.00 = $13.48 a $15.78 c $13.48 Max [$29.17 $35, 0] = $0.00 $13.48 $0.00 = $13.48 Range of Outcomes: $ 5.00 $5.00 $ 0.00 Notes: a The portfolio contains 0.462 share of stock, with a stock price of $34.16, so its value is 0.462($34.16) $15.78. b The ending stock price is $40, so the value is 0.462($40) $18.48. c The ending stock price is $29.17, so the value is 0.462($29.17) $13.48. The next step is to find the number of shares of stock needed to create the hedge portfolio for the starting portion of the lattice: N C u C d P u P d $13.21 $2.83 0.819 $46.84 $34.16 With 0.819 share of stock and one option in the hedge portfolio, the sixmonth values of the portfolio are shown in Figure 6E-9. Notice that the hedge portfolio in Figure 6E-9 will be $25.14 in six months no matter whether the stock goes up or down. Thus, the value of the portfolio should be the present value of this future value discounted at the risk-free rate. Therefore, if the current stock price is $40, then the current value of the portfolio is Portfolio value $25.14e 0.08(0.5) $24.154 Because the portfolio is comprised of a long position of N shares of the stock and a short position in the option, the current value of the option is value of option N(P) Portfolio value 0.819($40) $24.154 $8.61 There are many free binomial option-pricing programs on the Web, including one at http://www.hoadley.net/options/ calculators.htm. Thus, the option is currently worth $8.61. Notice that this is a little lower than the $8.71 price we estimated earlier with only one period in the year. If we break the year into smaller periods and allow the stock price to move up or down more often, the lattice would have a more realistic range of possible outcomes. Of course, estimating the current option price would require solving lots of binomial problems within the lattice, but each problem is very simple, and computers can solve them very rapidly. With more outcomes, the resulting estimated 6E-8 Chapter 6 Web Extension: The Binomial Approach

19878_06W_p001-009.qxd 3/10/06 9:53 AM Page 9 Figure 6E-8 Six-Month Values for the Starting Portion of the Binomial Lattice in Figure 6E-3 $46.84 Option Value $13.21 $46.84 $13.21 = $33.63 $34.16 $ 2.83 $34.16 $2.83 = $31.33 Range of Outcomes: $12.68 $10.38 $ 2.30 Figure 6E-9 The Hedge Portfolio for the Starting Portion of the Binomial Lattice in Figure 6E-3 b $38.35 Option Value $13.21 $38.35 $13.21 = $25.14 a $32.75 c $27.97 $ 2.83 $27.97 $2.83 = $25.14 Range of Outcomes: $10.38 $10.38 $ 0.00 Notes: a The portfolio contains 0.819 share of stock, with a stock price of $40, so its value is 0.819($40) $32.75. b The ending stock price is $46.84, so the value is 0.819($46.84) $38.35. c The ending stock price is $34.16, so the value is 0.819($32) $27.97. option price is more accurate. For example, if we divide the year into 10 periods, the estimated price is $8.38. With 100 periods, the price is $8.41. With 1,000, it is still $8.41, which shows that the solution converges to its final value with a relatively small number of steps. In fact, as we break the year into smaller and smaller periods, the solution for the binomial approach converges to the Black-Scholes solution. The binomial approach is widely used to value options with more complicated payoffs than the call option in our example. This is beyond the scope of a financial management textbook, but if you are interested in learning more about the binomial approach, take a look at the textbooks listed in the end-of-chapter references. Chapter 6 Web Extension: The Binomial Approach 6E-9