Extensions to the Black Scholes Model

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Lecture 16 Extensions to the Black Scholes Model 16.1 Dividends Dividend is a sum of money paid regularly (typically annually) by a company to its shareholders out of its profits (or reserves). In this lecture we are interested in how to model dividends in a stock model, and then how to include them into the Black-Scholes model. We present the most simple possible model for dividends, and that is to assume that in a time dt the underlying stock pays out a cash sum proportional to the stock price S equal to D 0 Sdt where D 0 is the constant dividend yield. Example 16.1. What happens to the stock price when a dividend is paid out? Solution 16.1. 136

In reality, dividends are paid out discretely on a regular basis, but we choose to model them as a continuous, proportional payment to make things easier. If we include the dividend payment in our stock model, we get ds = µsdt + σsdw D 0 Sdt D 0 Sdt }{{} cash paid to each shareholder 137

which we can rewrite as ds = (µ D 0 )Sdt + σsdw. Example 16.2. How do these dividend payments work in a portfolio? Solution 16.2. 138

16.2 Options on Dividend Paying Shares Now, we set up a portfolio consisting of a long position in one call option and a short position in shares. The value is Π = C S. Example 16.3. Show that the change in value of this portfolio in the time interval dt is dπ = dc ds D 0 Sdt. (16.1) Solution 16.3. Example 16.4. Using Itô s Lemma written like this: ( C dc = t + 1 ) 2 σ2 S 2 2 C S 2 dt + C ds, (16.2) S derive the modified Black-Scholes PDE: C t + 1 2 σ2 S 2 2 C S 2 + (r D 0)S C rc = 0. (16.3) S 139

Solution 16.4. 140

How can we find a solution to this modified Black-Scholes equation? The equation itself looks almost identical to (12.4), except we have an extra term multiplying the first derivative of S. Luckily there are a range of tricks we can use to solve a problem like this, by first guessing at the form of a solution and then seeing if the resulting equation is simplified in any way. To proceed, guess at a solution of the form C(S, t) = e D0(T t) C 1 (S, t). After this has been substituted into (16.3), we should find that C 1 satisfies the Black-Scholes equation except that the r is replaced by r D 0. Since we have already stated a solution to the Black-Scholes equation, we can then construct a solution to (16.3). In Examples Sheet 8 you should substitute C(S, t) = e D0(T t) C 1 (S, t) into (16.3) to show that the modified Black-Scholes equation has the explicit solution for the European call C(S, t) = Se D0(T t) N(d 10 ) Ee r(t t) N(d 20 ), (16.4) where and d 10 = ln(s/e) + (r D 0 + σ 2 /2)(T t) σ T t d 20 = d 10 σ T t. 141

16.3 Early Exercise Recall that an American Option is one that may be exercised at any time prior to expiry (t = T ). We have already discussed how this works in a discrete time binomial model, so what happens when we move to continuous time? Example 16.5. How do we price an American option in continuous time? Solution 16.5. In fact in the continuous limit, the resulting problem can be formulated and solved in several different ways Optimal Stopping Problem: this is popular with probability academics. The problem can be stated as the optimal time at which to exercise (and hence stop holding the option). Some results can be derived but to get an actual value one of the next two methods must be used. Variational Inequalities: this formulation is the most robust way to formulate the problem, and there are many numerical techniques (no analytic ones though) available to solve problems of this type. Free Boundary: this formulation is popular since it can means that analytic solutions can be derived in some cases. Unfortunately it is not very robust since assumptions have to be made about the existence of the barrier and numerical solutions are difficult to code although they are very accurate. As such, formulating and then valuing a contract such as this can be very difficult as there are often no explicit analytic solutions. 142

Example 16.6. Write the American put option problem as a free boundary problem (commonly found in fluid mechanics). Solution 16.6. 143