Section 1.4: Slope-Intercept Form

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Section 1.4: Slope-Intercept Form Objective: Give the equation of a line with a known slope and y-intercept. When graphing a line we found one method we could use is to make a table of values. However, if we can identify some properties of the line, we may be able to make a graph much quicker and easier. One such method is nding the slope and the y-intercept of the equation. The slope can be represented by m and the y- intercept, where it crosses the axis and x = 0, can be represented by (0; b) where b is the value where the graph crosses the vertical y-axis. Any other point on the line can be represented by (x; y). Using this information we will look at the slope formula and solve the formula for y. Example 1. m; (0; b); (x; y) Using the slope formula gives: y b x 0 = m Simplify y b = m Multiply both sides by x x y b = mx Add b to both sides +b +b y = mx + b Our Solution This equation, y = mx + b can be thought of as the equation of any line that has a slope of m and a y-intercept of b. This formula is known as the slope-intercept equation. Slope Intercept Equation: y = mx + b If we know the slope and the y-intercept we can easily nd the equation that represents the line. Example 2. Slope = 3 ; y intercept at (0; 3) 4 y = mx + b y = 3 4 x 3 Use the slope intercept equation m is the slope; b is the y intercept Our Solution We can also nd the equation by looking at a graph and nding the slope and y- intercept. 30

Example 3. Identify the point where the graph crosses the y-axis (0,3). This means the y-intercept is 3. Identy one other point and draw a slope triangle to nd the slope. The slope is 2 3 y = mx + b Slope-intercept equation y = 2 3 x + 3 Our Solution We can also move the opposite direction, using the equation identify the slope and y-intercept and graph the equation from this information. However, it will be important for the equation to rst be in slope intercept form. If it is not, we will have to solve it for y so we can identify the slope and the y-intercept. Example 4. Write in slope intercept form: 2x 4y = 6 Solve for y 2x 2x Subtract 2x from both sides 4y = 2x + 6 Put x term rst 4 4 4 Divide each term by 4 y = 1 2 x 3 2 Our Solution Once we have an equation in slope-intercept form we can graph it by rst plotting the y-intercept, then using the slope, nd a second point and connecting the dots. Example 5. Graph y = 1 2 x 4 y = mx + b m = 1 2 ; b = 4 Recall the slope intercept formula Identy the slope; m; and the y intercept; b Make the graph Starting with a point at the y-intercept of 4, Then use the slope rise, so we will rise run 1 unit and run 2 units to nd the next point. Once we have both points, connect the dots to get our graph. 31

World View Note: Before our current system of graphing, French Mathematician Nicole Oresme, in 1323 sugggested graphing lines that would look more like a bar graph with a constant slope! Example 6. Graph 3x + 4y = 12 Not in slope intercept form 3x 3x Subtract 3x from both sides 4y = 3x + 12 Put the x term rst 4 4 4 Divide each term by 4 y = 3 4 x + 3 y = mx + b m = 3 4 ; b = 3 Recall slope intercept equation Identy m and b Make the graph Starting with a point at the y-intercept of 3, Then use the slope rise, but it's negative so it will go downhill, so we will run drop 3 units and run 4 units to find the next point. Once we have both points, connect the dots to get our graph. We want to be very careful not to confuse using slope to nd the next point with using a coordinate such as (4; 2) to nd an individual point. Coordinates such as (4; 2) start from the origin and move horizontally rst, and vertically second. Slope starts from a point on the line that could be anywhere on the graph. The numerator is the vertical change and the denominator is the horizontal change. Lines with zero slope or no slope can make a problem seem very dierent. Zero slope, or horizontal line, will simply have a slope of zero which when multiplied by x gives zero. So the equation simply becomes y = b or y is equal to the y-coordinate of the graph. If we have no slope, or a vertical line, the equation can't be written in slope intercept at all because the slope is undened. There is no y in these equations. We will simply make x equal to the x-coordinate of the graph. Example 7. A driving service charges an initial service fee of S6 and an additional S3 per mile traveled. Construct an equation that expresses the total cost, y, for traveling x miles. Identify the slope and y-intercept, and their meaning in context to this problem. 32

It may be helpful to calculate the total cost for several cases. The S6 service fee is constant; every traveler will pay at least S6. Added to this service fee is S3 for every mile. The total costs for three cases follow. Mileage Total cost 7 6 + 3(7) = S27 8 6 + 3(8) = S30 9 6 + 3(9) = S33 If y represents the total charge and x represents the mileage, this can be generalized as y=6+3x Therefore, the slope is 3 and y-intercept is (0,6). The slope represents the average rate of change. As the mileage increases by 1 mile, the total cost increases by S3: This can be seen in the examples given when traveling 7; 8; or 9 miles: The y intercept represents the case where x; or mileage; is 0: When miles traveled is 0; meaning you just entered the vehicle; your cost is S6: Example 8. Give the equation of the line in the graph. Because we have a vertical line and no slope there is no slope-intercept equation we can use. Rather we make x equal to the x-coordinate of 4 x = 4 Our Solution 33

1.4 Practice Write the slope-intercept form of the equation of each line given the slope and the y-intercept. 1) Slope = 2, y-intercept = 5 3) Slope = 1, y-intercept = 4 5) Slope = 3, y-intercept = 1 4 7) Slope = 1 3, y-intercept = 1 2) Slope = 6, y-intercept = 4 4) Slope = 1, y-intercept = 2 6) Slope = 1, y-intercept = 3 4 8) Slope = 2, y-intercept = 5 5 Write the slope-intercept form of the equation of each line. 9) 10) 11) 12) 13) 14) 34

15) x + 10y = 37 17) 2x + y = 1 19) 7x 3y = 24 21) x = 8 23) y 4 = (x + 5) 25) y 4 = 4(x 1) 27) y + 5 = 4(x 2) 29) y + 1 = 1 (x 4) 2 16) x 10y = 3 18) 6x 11y = 70 20) 4x + 7y = 28 22) x 7y = 42 24) y 5 = 5 (x 2) 2 26) y 3 = 2 (x + 3) 3 28) 0 = x 4 30) y + 2 = 6 (x + 5) 5 Sketch the graph of each line. 31) y = 1 x + 4 3 33) y = 6 x 5 5 35) y = 3 x 2 37) x y + 3 = 0 39) y 4 + 3x = 0 41) 3y = 5x + 9 32) y = 1 x 4 5 34) y = 3 x 1 2 36) y = 3 x + 1 4 38) 4x + 5 = 5y 40) 8 = 6x 2y 42) 3y = 3 3 x 2 Consider each scenario and develop an applicable model. 43) The initial room temperature of a beverage is 70 o F. When placed in a particular refrigerator, the beverage is expected to cool (or decrease temperature) by an average of 5 o F per hour. Express the temperature of the beverage, y, after remaining in the refrigerator for x hours. Identify the slope and y-intercept, and identify their meaning in context to this problem. 44) A reloadable banking card has an initial cost of S4.95 and a service fee of S2.95 per month. Express the total cost, y, of maintaining this banking card for x months. Identify the slope and y-intercept, and identify their meaning in context to this problem. 35

1) y = 2x + 5 2) y = 6x + 4 3) y = x 4 4) y = x 2 5) y = 3 4 x 1 6) y = 1 4 x + 3 7) y = 1 3 x + 1 8) y = 2 5 x + 5 9) y = x + 5 10) y = 7 2 x 5 11) y = x 1 12) y = 5 3 x 3 13) y = 4x 14) y = 3 4 x + 2 15) y = 1 10 x 37 10 16) y = 1 10 x 3 10 17) y = 2x 1 18) y = 6 11 x + 70 11 19) y = 7 3 x 8 20) y = 4 7 x + 4 21) x = 8 22) y = 1 7 x + 6 23) y = x 1 24) y = 5 2 x 25) y = 4x 26) y = 2 3 x + 1 27) y = 4x + 3 28) x = 4 1.4 Answers 29) y = 1 x + 1 2 30) y = 6 x + 4 5 31) 32) 33) 34) 35) 36) 37) 38) 39) 40) 41) 42) 36

43) y=70-5x with slope -5 and y-intercept (0,70). The slope represents the average rate of change. As the hour increases by 1, the temperature decreases by 5. The y- intercept represents the temperature at 0 hours, or the initial temperature. 44) y=4.95+2.95x with slope 2.95 and y-intercept (0,4.95). The slope represents the average rate of change. As the month increases by 1, the total cost increases by 2.95. The y- intercept represents the total cost at 0 months, or the initial cost. 37