Black-Scholes-Merton Model

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Black-Scholes-Merton Model Weerachart Kilenthong University of the Thai Chamber of Commerce c Kilenthong 2017 Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 1 / 25

Main Issues Black-Scholes-Merton PDE. Black-Scholes-Merton Formula for a European option. Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 2 / 25

Lognormal Perperty of Stock Prices Consider the stock price process ds = µsdt + σsdz ds S = µdt + σdz (1) This implies that S S N ( µ t, σ 2 t ) (2) Using Ito s lemma, we can show that (by integration) ) ) ln S t ln S 0 N ((µ σ2 t, σ 2 t 2 (3) and ln S t N ( ln S 0 + ) ) (µ σ2 t, σ 2 t 2 (4) Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 3 / 25

Lognormal Perperty of Stock Prices: Example Consider a stock with an initial price $40, an expected return (rate) of 16% per annum, and a volatility of 20 % per annum. Using the equation before, the probability of stock price in 6 months (T = 0.5) from today is ln S T ( ) ) N ln 40 + (0.16 0.202 0.5, 0.20 2 0.5 2 N (3.759, 0.02) ) Note that E[S T ] = S 0 e µt and Var[S T ] = S0 (e 2e2µT σ2t 1. Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 4 / 25

The Distribution of the Rate of Return Let R be the continuously compounded rate of return per annum realized between times 0 and T. Then, by definition, and so S T = S 0 e RT (5) R = 1 T ln S T S 0 (6) Hence, R N ) (µ σ2 2, σ2 T (7) Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 5 / 25

The Distribution of the Rate of Return: Example Consider a stock with an expected return of 17% per annum, and a volatility of 20 % per annum. The continuously compounded ( rate of return ) per annum realized over 3 years is distributed N 0.17 0.202 2, 0.202 3. Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 6 / 25

Assumptions of BSM The stock price S follows Short selling is allowed. No transaction costs or taxes. Securities are perfectly divisible. No dividend during the life of derivatives. No arbitrage opportunities. Security trading is continuous. ds = µsdt + σsdz (8) The risk-free rate of interest, r, is constant and the same for all maturities. Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 7 / 25

Black-Scholes-Merton PDE: Derivation The main ideas are 1 to apply Ito s lemma on the option price process as a function of stock price, 2 and to use no arbitrage condition to set the price. Let S(t) be the stock price at time t, and T be the maturity date of the derivative. That is, the time to maturity is T t. Let f (S, t) be the price of the derivative at time t, and it depends on the stock price. Using Ito s lemma, we can show that [ f f df = µs + S t + 1 2 ] f 2 S 2 σ2 S 2 dt + f σsdz (9) S where dz = ϵ dt. Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 8 / 25

Black-Scholes-Merton PDE: Risk-Free Portfolio We can now form a risk-free portfolio by 1 short on the derivative: 1, 2 long the stock: f S. The value of the portfolio is Π = f + f S S (10) Hence, we can show that dπ = df + f [ f S ds = f µs + S t + 1 2 f f f σsdz + µsdt + S S S σsdz [ f = t + 1 2 ] f 2 S 2 σ2 S 2 dt 2 f S 2 σ2 S 2 Since this portfolio value does not have dz term, it is risk free. ] dt Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 9 / 25

Black-Scholes-Merton PDE: No-Arbitrage Using the no-arbitrage condition, dπ = r Πdt, [ f t + 1 2 ] f 2 S 2 σ2 S 2 dt = r ( f + f S S Hence, we get the Black-Scholes-Merton (stochastic) Partial Differential Equation (PDE) f t ) dt (11) f + rs S + 1 2 σ2 S 2 2 f = rf (12) S2 Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 10 / 25

Black-Scholes-Merton PDE: Boundary Condition The Black-Scholes-Merton (stochastic) Partial Differential Equation (PDE) f t f + rs S + 1 2 σ2 S 2 2 f = rf (13) S2 has many solutions, each of which is a tradeable derivative (satisfying the assumptions above) that will not create an arbitrage opportunity. To get the price of a specific derivative, we need to specify a boundary condition. For example, 1 European call option: f = max{s K, 0} when t = T, 2 European put option: f = max{k S, 0} when t = T Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 11 / 25

Black-Scholes-Merton PDE: Example In principle, we can try to solve an PDE with a boundary condition using mathematical program. But we will not do it in this class yet. We will just check if price of a derivative satisfies the PDE or not. Example: consider a forward price f = S Ke r(t t) (14) Ask students to show that it satisfies the BSM PDE. Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 12 / 25

Black-Scholes-Merton PDE: Arbitrage Example Now what if a price function does not satisfy the BSM PDE? Then there must be an arbitrage opportunity. Example: consider f = e S. It does not satisfies the BSM PDE. Consider the value of the risk-free portfolio in this case. dπ = [0 + 12 ] es σ 2 S 2 dt (15) There is an arbitrage opportunity if 1 2 es σ 2 S 2 r(e S e S S) > 0 1 2 σ2 S 2 + rs r > 0 (16) For example, if σ = 0.2, r = 0.1, you can show that you can arbitrage using this risk-free portfolio when 1.382 S 3.618. Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 13 / 25

Risk Neutral Evaluation Note that the BSM PDE does not depend on µ. On the other hand, µ (expected return required by investors) is the only part of stock price that depends on risk preferences. That is, BSM PDE is independent of risk preferences. hence, we can use any set of risk preferences to evaluate the value of derivatives. Hence, we will use risk neutral evaluation, which implies that 1 µ = r. Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 14 / 25

Risk Neutral Evaluation: Example Consider a forward contract on a non-dividend paying stock. Let K be the delivery price,a dn T is maturity. The value in risk neutral world is f = e rt E (S T K) = e rt E (S T ) e rt K = e rt S 0 e rt e rt K = S 0 e rt K Note that we use BSM model indirectly here. We use it to ensure that we can use risk neutral valuation (µ = r). Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 15 / 25

Black-Scholes-Merton Pricing Formulas We can solve the PDE for the pricing formulas. But it is beyond the scope of this class. We will use risk neutral valuation to get the pricing formulas at the end of the lecture. Let Φ(x) is the cumulative distribution function of the standard normal. Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 16 / 25

Black-Scholes-Merton Pricing Formulas The Black-Scholes-Merton pricing formulas at time t for European call and put options with maturity at T, respectively, c = S 0 Φ(d 1 ) Ke r(t t) Φ(d 2 ) (17) p = Ke r(t t) Φ( d 2 ) S 0 Φ( d 1 ) (18) where d 1 = d 2 = ln S 0 K + ( ln S 0 K + ( r + σ2 2 σ T t r σ2 2 σ T t ) (T t) ) (T t) (19) = d 1 σ T t (20) Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 17 / 25

Black-Scholes-Merton Pricing Formulas: Interpretation Using risk neutral evaluation, we can write (the price at the beginning) c = e rt E [max{s K, 0}] (21) Using the formula above we can rewrite it as [ ] c = e rt S 0 e rt Φ(d 1 ) KΦ(d 2 ) (22) S 0 Φ(d 1 ) is the expected value in risk-neutral world of a variable that is equal to S T if S T K > 0 and to zero otherwise. KΦ(d 2 ) is the expected cost if the buyers exercise the option. Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 18 / 25

Black-Scholes-Merton Pricing Formulas: Double Check We will now check whether the formula can apply to simpler derivatives that we know their prices. First, consider a forward contract whose price is S 0 Ke rt. A forward contract can be considered as a call option when S 0 is so large that almost certain that it will be exercised. When S 0 is so large, we will get d 1 and d 2 are also very large. that means Φ(d 1 ) Φ(d 2 ) 1. Therefore, the price is c = S 0 Φ(d 1 ) Ke r(t t) r(t t) Φ(d 2 ) = S 0 Ke Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 19 / 25

Black-Scholes-Merton Pricing Formulas: Double Check Second, consider when σ approaches zero. That means it is almost certain that the stock price at time T will be e rt S 0. Hence, the payoff of the option is max{e rt S 0 K, 0}. The value of the option today is max{s 0 e rt K, 0}. Now consider the BSM formula. 1 Case I: when S 0 > e rt K. As σ 0, we can show that d 1, d 2. This we get c = S 0 Ke r(t t). 2 Case II: when S 0 < e rt K. As σ 0, we can show that d 1, d 2. This case Φ(d 1 ) Φ(d 2 ) 0. hence, c = 0. Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 20 / 25

Option Pricing with Dividend For European options we can simply value the dividend stream as riskless part separately. Then, the BSM applies to the risky part. Example: Consider a European call option on a stock when there are ex-dividend dates in 2 months and in 5 months. The dividend is expected to be $0.50. Let S 0 = 40, K = 40, σ = 0.30, r = 0.09, T = 0.5. We can first calculate the discounted value of the dividend stream: 0.50 0.09 2 12 +0.50 0.09 5 12 = 0.9742 (23) Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 21 / 25

Option Pricing with Dividend The effective price of risky part of the stock is S 0 0.9742 = 39.0258. Hence, we have d 1 = 0.2020, d 2 = 0.0102 Φ(d 1 ) = 0.5800, Φ(d 2 ) = 0.4959. Using the BSM formula, we can get c = 39.0258 0.5800 40 e 0.09 0.50 0.4959 = 3.67 Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 22 / 25

Estimating Volatility from Historical Data: Simple Method Since we assume that the process of u t = ln S t S t 1 is distributed normal ( N µ σ2 2 ),, σ2 we can simply calculate SD of this process using where t = 0, 1,..., T. s = 1 T (u t ū) n 1 2 (24) t=1 This SD is σ t where t is the length of time of each period of the data in unit of the length of time we want to have. Hence, we can estimate the volatility using ˆσ = s t (25) Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 23 / 25

Estimating Volatility from Historical Data: Example Consider data of 21 consecutive trading days of a stock price. So, T = 20. Let T T u i = 0.09531, ui 2 = 0.00326 t=1 t=1 Hence, s = 0.00326 0.095312 19 20 19 = 0.01216 Given that there are 252 trading days per year, t = 1 252. Hence, the volatility per annum is 0.01216 252 = 0.193. Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 24 / 25

Implied Volatility We can also estimate volatility using option prices already traded in the market. In this case, we do not need to know the process of S directly since BSM formula do not need µ and σ is our unknown anyway. Example: there is a European call option on a non-dividend-paying stock whose value is c = 1.875. Let S 0 = 21, K = 20, r = 0.10, T = 0.25. What is σ? We can get σ using BSM formula (17) by substituting S 0 = 21, K = 20, r = 0.10, T = 0.25 into the equation and solve for σ that gives c = 1.875. You can use Matlab or even Excel to solve for this. Weerachart Kilenthong University of the Thai Chamber Black-Scholes-Merton of Commerce Model 25 / 25