Lecture 37 Sections 11.1, 11.2, Mon, Mar 31, Hampden-Sydney College. Independent Samples: Comparing Means. Robb T. Koether.

Similar documents
Lecture 18 Section Mon, Feb 16, 2009

Lecture 18 Section Mon, Sep 29, 2008

Standard Deviation. Lecture 18 Section Robb T. Koether. Hampden-Sydney College. Mon, Sep 26, 2011

Lecture 39 Section 11.5

Lecture 35 Section Wed, Mar 26, 2008

Installment Loans. Lecture 23 Section Robb T. Koether. Hampden-Sydney College. Mon, Mar 23, 2015

The t Test. Lecture 35 Section Robb T. Koether. Hampden-Sydney College. Mon, Oct 31, 2011

Distribution. Lecture 34 Section Fri, Oct 31, Hampden-Sydney College. Student s t Distribution. Robb T. Koether.

Chapter 3 - Lecture 3 Expected Values of Discrete Random Va

7. For the table that follows, answer the following questions: x y 1-1/4 2-1/2 3-3/4 4

7.1 Comparing Two Population Means: Independent Sampling

Section 6.5. The Central Limit Theorem

15.063: Communicating with Data Summer Recitation 4 Probability III

Experimental Design and Statistics - AGA47A

Using the Central Limit Theorem It is important for you to understand when to use the CLT. If you are being asked to find the probability of the

Discrete Random Variables

Discrete Random Variables

No, because np = 100(0.02) = 2. The value of np must be greater than or equal to 5 to use the normal approximation.

As you draw random samples of size n, as n increases, the sample means tend to be normally distributed.

Municipal Bonds. Lecture 3 Section Robb T. Koether. Hampden-Sydney College. Mon, Aug 29, 2016

Chapter 3 - Lecture 4 Moments and Moment Generating Funct

Chapter 5 Discrete Probability Distributions. Random Variables Discrete Probability Distributions Expected Value and Variance

Independent-Samples t Test

Examples CH 4 X P(X).2.3?.2

The Central Limit Theorem. Sec. 8.2: The Random Variable. it s Distribution. it s Distribution

Standard Normal, Inverse Normal and Sampling Distributions

Municipal Bonds. Lecture 20 Section Robb T. Koether. Hampden-Sydney College. Fri, Mar 6, 2015

Version A. Problem 1. Let X be the continuous random variable defined by the following pdf: 1 x/2 when 0 x 2, f(x) = 0 otherwise.

First Exam for MTH 23

Lecture 23. STAT 225 Introduction to Probability Models April 4, Whitney Huang Purdue University. Normal approximation to Binomial


Lecture 8: Single Sample t test

Value (x) probability Example A-2: Construct a histogram for population Ψ.

Previously, when making inferences about the population mean, μ, we were assuming the following simple conditions:

Economics 483. Midterm Exam. 1. Consider the following monthly data for Microsoft stock over the period December 1995 through December 1996:

Inflation Purchasing Power

Tutorial 6. Sampling Distribution. ENGG2450A Tutors. 27 February The Chinese University of Hong Kong 1/6

* Point estimate for P is: x n

Sampling Distribution

Statistics for Business and Economics: Random Variables:Continuous

Inflation. Lecture 7. Robb T. Koether. Hampden-Sydney College. Mon, Sep 4, 2017

Review: Population, sample, and sampling distributions

Econ 424/CFRM 462 Portfolio Risk Budgeting

Chapter 7 - Lecture 1 General concepts and criteria

Inflation. Lecture 7. Robb T. Koether. Hampden-Sydney College. Mon, Jan 29, 2018

Discrete Random Variables

8.1 Estimation of the Mean and Proportion

MATH 10 INTRODUCTORY STATISTICS

Introduction to Probability

MATH 10 INTRODUCTORY STATISTICS

Installment Loans. Lecture 7 Section Robb T. Koether. Hampden-Sydney College. Wed, Sep 7, 2016

Statistics 511 Additional Materials

Chapter 7 Study Guide: The Central Limit Theorem

Probability Theory and Simulation Methods. April 9th, Lecture 20: Special distributions

Installment Loans. Lecture 6 Section Robb T. Koether. Hampden-Sydney College. Fri, Jan 26, 2018

Mean GMM. Standard error

Chapter 8: The Binomial and Geometric Distributions

Inflation. Lecture 7. Robb T. Koether. Hampden-Sydney College. Mon, Sep 10, 2018

Review of the Topics for Midterm I

Lecture 2 INTERVAL ESTIMATION II

Expected Value and Variance

HOMEWORK: Due Mon 11/8, Chapter 9: #15, 25, 37, 44

Hypothesis Tests: One Sample Mean Cal State Northridge Ψ320 Andrew Ainsworth PhD

I. Standard Error II. Standard Error III. Standard Error 2.54

Random Variables and Applications OPRE 6301

Installment Loans. Lecture 6 Section Robb T. Koether. Hampden-Sydney College. Fri, Sep 7, 2018

TWO μs OR MEDIANS: COMPARISONS. Business Statistics

Chapter 7. Inferences about Population Variances

Lecture 22. Survey Sampling: an Overview

ECON 214 Elements of Statistics for Economists 2016/2017

19. CONFIDENCE INTERVALS FOR THE MEAN; KNOWN VARIANCE

INFERENTIAL STATISTICS REVISION

6 Central Limit Theorem. (Chs 6.4, 6.5)

Honors Statistics. Daily Agenda

Making Sense of Cents

ECE 340 Probabilistic Methods in Engineering M/W 3-4:15. Lecture 10: Continuous RV Families. Prof. Vince Calhoun

Linear Regression with One Regressor

ECON FINANCIAL ECONOMICS

σ e, which will be large when prediction errors are Linear regression model

Two Populations Hypothesis Testing

Diploma in Business Administration Part 2. Quantitative Methods. Examiner s Suggested Answers

Uniform Probability Distribution. Continuous Random Variables &

Lecture 6: Chapter 6

The Two-Sample Independent Sample t Test

Techniques for Calculating the Efficient Frontier

The Normal Approximation to the Binomial

STOR Lecture 15. Jointly distributed Random Variables - III

ECON 214 Elements of Statistics for Economists

Chapter 6: Random Variables

MS-E2114 Investment Science Lecture 5: Mean-variance portfolio theory

5.2 Random Variables, Probability Histograms and Probability Distributions

5/5/2014 یادگیري ماشین. (Machine Learning) ارزیابی فرضیه ها دانشگاه فردوسی مشهد دانشکده مهندسی رضا منصفی. Evaluating Hypothesis (بخش دوم)

Name PID Section # (enrolled)

Confidence Intervals: Review

Discrete Random Variables

STAT 1220 FALL 2010 Common Final Exam December 10, 2010

MA 1125 Lecture 14 - Expected Values. Wednesday, October 4, Objectives: Introduce expected values.

Statistics for Managers Using Microsoft Excel 7 th Edition

MA 1125 Lecture 12 - Mean and Standard Deviation for the Binomial Distribution. Objectives: Mean and standard deviation for the binomial distribution.

Converting to the Standard Normal rv: Exponential PDF and CDF for x 0 Chapter 7: expected value of x

Transcription:

: : Lecture 37 Sections 11.1, 11.2, 11.4 Hampden-Sydney College Mon, Mar 31, 2008

Outline : 1 2 3 4 5

: When two samples are taken from two different populations, they may be taken independently or not independently. When they are not independent, the data are usually paired and we study the difference between the pairs. When they are independent, the best we can do is study the difference between the averages of the samples. We will study only the independent samples. In this lecture, we will learn how to test a hypothesis concerning the difference between the population means. We will also learn how to perform the test on the TI-83.

: In a paired study, two observations are made on each subject, producing one sample of bivariate data. Or we could think of it as two samples of paired data. Paired data are often before" and after" observations. By comparing the mean before treatment to the mean after treatment, we can determine whether the treatment had an effect.

: On the other hand, with independent samples, there is no logical way to pair" the data. One sample might be from a population of males and the other from a population of (unrelated) females. Of course, males and females could be paired if they were twins or husband and wife. Or one might be the treatment group and the other the control group. Furthermore, the independent samples could be of different sizes. Paired samples must be of the same size.

The Estimator of µ 1 µ 2 : We start with two populations. Population 1 has mean µ 1 and standard deviation σ 1. Population 2 has mean µ 2 and standard deviation σ 2. We wish to compare µ 1 and µ 2. We do so by taking samples and comparing sample means x 1 and x 2.

The Estimator of µ 1 µ 2 : We will use as an estimator of µ 1 µ 2. If we want to know whether µ 1 = µ 2, we test to see whether µ 1 µ 2 = 0 by computing and comparing it to 0.

The Distributions of x 1 and x 2 : Let n 1 and n 2 be the sample sizes. If the samples are large, then x 1 and x 1 have (approx.) normal distributions. However, if either sample is small, then we will need an additional assumption: The population of the small sample(s) is normal. in order to use the t distribution.

Further Assumption : We will also assume that the two populations have the same standard deviation. Call it σ. That is, σ = σ 1 = σ 2. If this assumption is not supported by the evidence, then it should not be made. If this assumption is not made, then the formulas become much more complicated. See p. 658.

The : If the sample sizes are large enough (or the populations are normal), then according to the Central Limit Theorem, x 1 has a normal distribution with mean µ 1 and standard deviation σ 1 n1. x 2 has a normal distribution with mean µ 2 and standard deviation σ 2 n2.

Some Statistical Facts : 1 For any two random variables X and Y µ X+Y = µ X + µ Y σx+y 2 = σx 2 + σ2 Y σ X+Y = σx 2 + σ2 Y 2 If X and Y are both normal X + Y is also normal.

Some More Statistical Facts : 1 For the difference X Y, the situation is very similar. 2 For any two random variables X and Y µ X Y = µ X µ Y σx Y 2 = σx 2 + σ2 Y σ X Y = σx 2 + σ2 Y 3 If X and Y are both normal X Y is also normal.

The : It follows from theory that is normal with Mean µ x 1 x 2 = µ 1 µ 2 Variance Standard deviation σ 2 x 1 x 2 = σ2 1 n 1 + σ2 2 n 2 σ x 1 x 2 = σ 2 1 n 1 + σ2 2 n 2

The : If we assume that σ 1 = σ 2, (call it σ), then the standard deviation may be simplified to σ σ x 1 x 2 = 2 + σ2 1 = σ + 1 n 1 n 2 n 1 n 2

The x 1 : x 1 is N 5, 6 36 0 µ 1 µ 2 µ 2 µ 1

The x 2 : x 2 is N 3, 6 36 0 µ 1 µ 2 µ 2 µ 1

The : x1 x2 is N 2 2,6 36 0 µ 1 µ 2 µ 2 µ 1

The : If is normal with mean µ x 1 x 2 = µ 1 µ 2 and standard deviation 1 σ + 1, n 1 n 2 then it follows that Z = ( ) (µ 1 µ 2 ) σ 1 n 1 + 1 n 2

Example : Work exercise 11.32 on page 716 under the assumption that σ = 6 for both populations. Which route to work is shorter, Route 1 or Route 2? Route 1 Route 2 n 1 = 40 n 2 = 40 x 1 = 31.945 x 2 = 28.105 Assume that σ = 6. Test hypotheses at 5% level.

: In dependent samples, the data are usually paired and we study the difference between the pairs. In independent samples, we study the difference between the sample means. The statistic has a normal distribution if the populations are normal or if the sample sizes are large enough. Under the simplest circumstances, the statistic is Z = ( ) (µ 1 µ 2 ). σ 1 n 1 + 1 n 2