r 1. Discuss the meaning of compounding using the formula A= A0 1+

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Money and the Exponential Function Goals: x 1. Write and graph exponential functions of the form f ( x) = a b (3.15) 2. Use exponential equations to solve problems. Solve by graphing, substitution. (3.17) 3. Use exponential equations of the form f ( x) = (1 + r) x where r is given as a rate of growth or decay to solve problems. (4.03) 4. Find the Annual Percentage Rate (APR) for a given compounded rate. Materials and Equipment needed by each student: 1. Copy of the student handout 2. Calculator 3. Paper and pencil for note taking. Activity One: Compound Interest A friend borrows $300 from you for maximum of thirty days. You charge your friend either1% per day or 30% (once) for entire 30 days for the use of your money. Compare the amounts your friend owes you. 1. Define compound interest as interest gained on the balance (amount borrowed and past interest). 2. For the 30%: Calculate $300(1 + 0.30) = $390.00 30 3. On compounded interest: Evaluate $300(1 + 0.01) = $404.35 4. Clearly the borrower would like the 30% and the lender would like 1% per day. 5. What is the full 30-day rate that is the same as 1% per day for 30 days? Evaluate: 30 (1 + 0.01) = 1.347 which shows a rate of 34.7% for the full 30 days. Activity Two: Savings Account Lindsey s grandmother gave her $1000 on the day she was born. Lindsey s parents put the money into a savings account that earns 6.4% interest each year. a. How much money will Lindsey have in the account on her 1 th birthday if the interest is compounded annually, quarterly, monthly, daily, hourly, each minute, each second, continuously? b. In banking, the term Annual Percentage Rate (APR) is used to give the value of the annual simple interest rate that is equal to the compounded rate of an account. What is the APR for 6.4% each of the compounding schemes above? r 1. Discuss the meaning of compounding using the formula A= A0 1+ n, where A = the initial investment, r = the annual rate, n = number of times compounded in 0 nt Money and the Exponential Function 1 NCSSM Distance Learning

the year, and t = number of years. Discuss the values of each of these variables in this problem. 2. Use the 2 nd Enter aspect of the calculator to re-enter the equation just used and then by editing find the value for each of the 1 year compounding methods. n r 3. To find the APR, find the value of 1+. This value will determine the amount n that the principal is multiplied by each year or by subtracting 1, gives the annual rate the principal is multiplied by each year. Compounded nt r Value APR Formula: A= A0 1+ n annually 11.064 $3054.56 0.06400 $10001+ 1 quarterly 41.064 $3135.79 0.06555 $10001+ 4 monthly 121.064 $3154.4 0.065911 $10001+ 12 daily 3651.064 $3164.19 0.06606 $10001+ 365 hourly 365 241.064 $3164.50 0.066092 $10001+ 365 24 every minute 365 24 601.064 $3164.51 0.066092 $10001+ 365 24 60 every second 365 24 60 601.064 $3164.46 0.066092 $10001+ 365 24 60 60 continuously 0.0641 $1000 e $3164.51 0.066092 Note the technology begins to fail with the evaluation of compounding every second. This result is probably not reliable. Activity Two point Seven: What is e? One dollar is invested at 100% interest per year for a year. How much money is in the account at the end of the year? What value does the amount in the account approach as the number of compounding periods increases? 1 1. One dollar invested at 100% interest per year for a year would yield $1(1 + 1) = $2. 2. The table below will illustrate the value that the account approaches: Compounded formula amount Yearly 1 $1(1 + 1) $2 Monthly 12 1 $2.61303529 $11+ 12 Money and the Exponential Function 2 NCSSM Distance Learning

Daily 365 1 $11+ 365 Hourly 365 24 1 $11+ 365 24 every minute 365 24 60 1 $11+ 365 24 60 The value of e = 2.71212 which helps us see the definition of Follow Up: Several Applications $2.7145674 $2.7112669 $2.7127922 1 e = lim1+ n n. The following questions from the Indicators prepared by the NC Department of Public Instruction. 1. The number of airline passengers increased from 465.6 million in 1990 to 614.3 million in 199. What was the average annual growth rate (percent) for the 1990 to 199 period? If that rate remains constant after 199, how many airline passengers can be expected in 2005? Give the algebraic model for this growth. 2. At the end of four years (t), a savings account paying 5.35% annually ( r ) compounded continuously had a balance (B) of $3096.56. What was the initial deposit (P)? (Use B = Pe rt ) If the initial deposit had been in an account compounded annually, how much less interest would have been earned? 2 3. Solve 350 = 200e r for r. Justify each step. 4. Solve 960 = A 1.075 for A. Justify each step. 5. Solve 663 = 49 2.165 x for x. Justify each step. Each of these problems is simplified by using the graphing calculator. 1. In this question, the two points can become ordered pairs with the x-values in L1 and the y-values in L2. Use 0 for 1990 and for 199. Using ExpReg from the Stat Calc menu, the calculator produces the function y = 465.6(1.03525) x. Since x-values are years, we know that each year the number of riders is multiplied by 1.03525. This creates an annual growth rate of 3.525% each year. To find the number of passengers in 2005, find the value of Y1(15) since 2005 is 15 years from 1990. This result is 72.9, which is the number of passengers expected in 2005. The algebraic model is y = 465.6(1.03525) x. n Money and the Exponential Function 3 NCSSM Distance Learning

2. When we substitute the values given into the equation, the result is 0.05354 0.05354 3096.56 = Be. Solve this by finding the value of e. 0.05354 3096.56 = Be 3096.56 = B 1.23622655 3096.56 = B 1.23622655 2500.00 = B 0.0535 With annual compounding, the equation would be P = 25001+ = 3079.49 1 This will result is $17.07 less than with continuous compounding. 2 3. Graph y = 350 and y = 200e r on the same window. Use the intersect option on the calculator. A window that shows the intersection is 0 < x< 5,0 < y< 400. The point of intersection occurs at (0.279,350). Therefore, r = 0.279 4. By finding the value of 1.075 and substituting this value into the equation, 960 = A 1.075 960 = A 1.7347726 960 = A 1.7347726 53.274 = A 5. In this question, graph two functions y = 663 and y = 49 2.165 x. A window that shows the intersection is 0 < x< 5,0 < y< 00. The point of intersection occurs at (3.37246,663). Therefore, the solution is x = 3.37246. 4 Money and the Exponential Function 4 NCSSM Distance Learning

Student Handout Money and the Exponential Function 1. A friend borrows $300 from you for maximum of thirty days. You charge your friend 1% per day or 30% for entire 30 days for the use of your money. Compare the amounts your friend owes you. 2. Lindsey s grandmother gave her $1000 on the day she was born. Lindsey s parents put the money into a savings account that earns 6.4% interest each year. a. How much money will Lindsey have in the account on her 1 th birthday if the interest is compounded annually, quarterly, monthly, daily, hourly, each minute, each second, continuously? b. In banking, the term Annual Percentage Rate (APR) is used to give the value of the annual simple interest rate that is equal to the compounded rate of an account. What is the APR for 6.4% each of the compounding schemes above? nt Compounded r Value APR Formula: A= A0 1+ n annually quarterly monthly Daily hourly every minute every second continuously 2.7. One dollar is invested at 100% per year for a year. How much money is in the account at the end of the year? What value does the amount in the account approach as the number of compounding periods increases? Money and the Exponential Function 5 NCSSM Distance Learning

Follow Up Money and the Exponential Function The following questions from the Indicators prepared by the NC Department of Public Instruction. 1. The number of airline passengers increased from 465.6 million in 1990 to 614.3 million in 199. What was the average annual growth rate (percent) for the 1990 to 199 period? If that rate remains constant after 199, how many airline passengers can be expected in 2005? Give the algebraic model for this growth. 2. At the end of four years (t), a savings account paying 5.35% annually ( r ) compounded continuously had a balance (B) of $3096.56. What was the initial deposit (P)? (Use B = Pe rt ) If the initial deposit had been in an account compounded annually, how much less interest would have been earned? 3. Solve = e for r. Justify each step. 2 350 200 r 4. Solve = A for A. Justify each step. 960 1.075 5. Solve 663 = 49 2.165 x for x. Justify each step. Money and the Exponential Function 6 NCSSM Distance Learning